Question

In Problems 33– 44, find the one-sided limit.

$\underset{x\to -2^{+}}{\lim }(3x^2-8)$

Short answer

The limit value is

$\underset{x\to -2^{+}}{\lim }(3x^2-8)=4$

Step-by-step solution

step 1.introduction

Given limit

$\underset{x\to -2^{+}}{\lim }(3x^2-8)$

step 2.explantion

Consider the limits

$$\begin{gathered} \underset{x\to -2^{+}}{\lim }(3x^2-8)=(3{\left(-2\right)}^2-8) \\ =\left(3\right(4)-8) \\ =(12-8) \\ =4 \end{gathered}$$

step 3.the solution

the limit value

$\underset{x\to -2^{+}}{\lim }(3x^2-8)=4$