Question

In Problems 7– 42, find each limit algebraically.

$\underset{x\to 0}{\lim }\sqrt{1-2x}$.

Short answer

The answer is 1.

Step-by-step solution

Step. 1 Given Information

Given is the limit on which x tends to 1 and the function given is:

$\sqrt{1-2x}$

Step. 2 Solving the limit 

Firstly, we check whether the given function is in indeterminant form or not.

Since if we put $x=0$then it doesn't create any indeterminant form. So, to solve the limit we can directly put the value of x in the function. So,

$$\begin{gathered} \underset{x\to 0}{\lim }\sqrt{1-2x}=\sqrt{1-2\left(0\right)} \\ =\sqrt{1-0} \\ =\sqrt{1}=1. \end{gathered}$$