Question

For the function$$\begin{gathered} f\left(x\right)=\{x^2,ifx\le 0 \\ x+1,if0<x<2 \\ 5-x,if2\le x\le 5 \end{gathered}$$find$f\left(0\right)$and$f\left(2\right)$

Short answer

The value is$2,3$respectively

Step-by-step solution

Given information

Given function$$\begin{gathered} f\left(x\right)=\{x^2,x\le 0 \\ x+1,if0<x<2 \\ 5-x,if2\le x\le 5 \end{gathered}$$

Check the values satisfying the limits and calculate

For $x=0$,

$f\left(x\right)=x^2$

$$\begin{gathered} f\left(0\right)=0^2 \\ f\left(0\right)=0 \end{gathered}$$

For $x=2$

role="math" localid="1646982263287" $f\left(x\right)=5-x$

role="math" localid="1646982273636" $$\begin{gathered} f\left(2\right)=5-2 \\ f\left(2\right)=3 \end{gathered}$$