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Describe the transformations that must be applied to the graph of each exponential function \(f(x)\) to obtain the transformed function. Write each transformed function in the form \(y=a(c)^{b(x-h)}+k\). a) \(f(x)=\left(\frac{1}{2}\right)^{x}, y=f(x-2)+1\) b) \(f(x)=5^{x}, y=-0.5 f(x-3)\) c) \(f(x)=\left(\frac{1}{4}\right)^{x}, y=-f(3 x)+1\) d) \(f(x)=4^{x}, y=2 f\left(-\frac{1}{3}(x-1)\right)-5\)

Short Answer

Expert verified
a) \(y= \left(\frac{1}{2}\right)^{x-2} + 1\), b) \(y= -0.5 \, 5^{x-3}\), c) \( y= - \left( \frac{1}{4} \right)^{3x} + 1 \), d) \(y= 2 \, 4^{-\frac{x-1}{3}} - 5\)

Step by step solution

01

Identify the original function

For each sub-problem, start by writing down the given original exponential function.
02

Rewrite in standard form for a)

Given: \(f(x)=\left(\frac{1}{2}\right)^{x}, y=f(x-2)+1\).The transformations are a horizontal shift to the right by 2 units and a vertical shift up by 1 unit.The transformed function is \(y= \left(\frac{1}{2}\right)^{x-2} + 1\).
03

Rewrite in standard form for b)

Given: \(f(x)=5^{x}, y=-0.5 f(x-3)\).The transformations are a horizontal shift to the right by 3 units, a vertical stretch by a factor of 0.5, and a reflection across the y-axis.The transformed function is \(y= -0.5 \, 5^{x-3}\).
04

Rewrite in standard form for c)

Given: \(f(x)=\left(\frac{1}{4}\right)^{x}, y=-f(3 x)+1\).The transformations are a horizontal compression by a factor of \(\frac{1}{3}\), a reflection across the y-axis, and a vertical shift up by 1 unit.The transformed function is \( y= - \left( \frac{1}{4} \right)^{3x} + 1 \).
05

Rewrite in standard form for d)

Given: \(f(x)=4^{x}, y=2 f\left(-\frac{1}{3}(x-1)\right)-5\).The transformations are a horizontal shift to the right by 1 unit, a horizontal stretch by a factor of 3 (inverting the sign for a horizontal reflection), a vertical stretch by a factor of 2, and a vertical shift down by 5 units. The transformed function is \(y= 2 \, 4^{-\frac{x-1}{3}} - 5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Shift
A horizontal shift in exponential functions involves moving the entire graph of the function left or right. The general form for this transformation is given by replacing each occurrence of the variable inside the function with another expression that includes added or subtracted constants.

For example, if you have the function \(f(x) = 3^x\) and you shift it to the right by 2 units, the transformed function will be \(g(x) = 3^{x-2}\).

This moves every point on the graph of \(f(x)\) 2 units to the right. Conversely, if the function is shifted left by 2 units, the transformation will look like \(g(x) = 3^{x+2}\).

Horizontal shifts do not affect the shape of the graph; they only change its position along the x-axis.
Vertical Shift
A vertical shift involves moving the graph of the exponential function up or down. The standard form for this transformation is achieved by adding or subtracting constants outside the function.

For instance, if we start with \(f(x) = 2^x\) and apply a vertical shift 3 units upward, the new function becomes \(g(x) = 2^x + 3\).

This moves every point on the graph of \(f(x)\) 3 units up, without altering the shape of the graph. Similarly, if we shift the function down by 3 units, we get \(g(x) = 2^x - 3\).

Vertical shifts are straightforward and only modify the y-values of the function.
Reflection
Reflections can occur across both the x-axis and y-axis. Reflecting an exponential function across the x-axis flips the graph upside down.

This is done by multiplying the entire function by -1. For example, \(f(x) = 2^x\) reflected across the x-axis becomes \(g(x) = -2^x\).

Reflecting across the y-axis involves changing the sign of the variable inside the function. The function \(f(x) = 2^x\) reflected across the y-axis becomes \(g(x) = 2^{-x}\).

Reflections change the orientation but maintain the overall shape of the graph.
Vertical Stretch/Compression
A vertical stretch or compression changes the steepness of the exponential graph. This is accomplished by multiplying the whole function by a positive constant.

If the constant is greater than 1, the graph stretches vertically. For example, if \(f(x) = 3^x\) becomes \(g(x) = 2 \times 3^x\), the graph will stretch vertically by a factor of 2.

If the constant is between 0 and 1, the graph compresses. For example, \(g(x) = 0.5 \times 3^x\) will compress the graph vertically by a factor of 0.5.

Vertical stretch/compression affects the y-values while keeping the x-values unchanged.
Horizontal Stretch/Compression
Horizontal stretch or compression involves changing the width of the graph. This transformation is applied by multiplying the variable inside the function by a positive constant.

If the constant is greater than 1, the graph compresses horizontally. For instance, \(f(x) = e^x\) transformed by \(g(x) = e^{2x}\) compresses horizontally by a factor of 2.

If the constant is between 0 and 1, the graph stretches horizontally. For example, \(g(x) = e^{0.5x}\) will stretch the graph horizontally by a factor of 2.

Horizontal stretch/compression affects the x-values, thus changing the width of the graph.

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Most popular questions from this chapter

The CANDU (CANada Deuterium Uranium) reactor is a Canadian-invented pressurized heavy-water reactor that uses uranium-235 (U-235) fuel with a half-life of approximately 700 million years. a) What exponential function can be used to represent the radioactive decay of \(1 \mathrm{kg}\) of U-235? Define the variables you use. b) Graph the function. c) How long will it take for \(1 \mathrm{kg}\) of \(\mathrm{U}-235\) to decay to 0.125 kg? d) Will the sample in part c) decay to \(0 \mathrm{kg} ?\) Explain.

If seafood is not kept frozen (below \(0^{\circ} \mathrm{C}\) ), it will spoil due to bacterial growth. The relative rate of spoilage increases with temperature according to the model \(R=100(2.7)^{\frac{T}{s}},\) where \(T\) is the temperature, in degrees Celsius, and \(R\) is the relative spoilage rate. a) Sketch a graph of the relative spoilage rate \(R\) versus the temperature \(T\) from \(0^{\circ} \mathrm{C}\) to \(25^{\circ} \mathrm{C}\) b) Use your graph to predict the temperature at which the relative spoilage rate doubles to \(200 .\) c) What is the relative spoilage rate at \(15^{\circ} \mathrm{C} ?\) d) If the maximum acceptable relative spoilage rate is \(500,\) what is the maximum storage temperature?

A savings bond offers interest at a rate of \(6.6 \%\) per year, compounded semi-annually. Suppose that you buy a S500 bond. a) Write an equation for the value of the investment as a function of time, in years. b) Determine the value of the investment after 5 years. c) How long will it take for the bond to triple in value?

Money in a savings account earns compound interest at a rate of \(1.75 \%\) per year. The amount, \(A,\) of money in an account can be modelled by the exponential function \(A=P(1.0175)^{n}\) where \(P\) is the amount of money first deposited into the savings account and \(n\) is the number of years the money remains in the account. a) Graph this function using a value of \(P=\$ 1\) as the initial deposit. b) Approximately how long will it take for the deposit to triple in value? c) Does the amount of time it takes for a deposit to triple depend on the value of the initial deposit? Explain. d) In finance, the rule of 72 is a method of estimating an investment's doubling time when interest is compounded annually. The number 72 is divided by the annual interest rate to obtain the approximate number of years required for doubling. Use your graph and the rule of 72 to approximate the doubling time for this investment.

If a given population has a constant growth rate over time and is never limited by food or disease, it exhibits exponential growth. In this situation, the growth rate alone controls how quickly (or slowly) the population grows. If a population, \(P,\) of fish, in hundreds, experiences exponential growth at a rate of \(10 \%\) per year, it can be modelled by the exponential function \(P(t)=1.1^{t},\) where \(t\) is time, in years. a) Why is the base for the exponential function that models this situation \(1.1 ?\) b) Graph the function \(P(t)=1.1^{t} .\) What are the domain and range of the function? c) If the same population of fish decreased at a rate of \(5 \%\) per year, how would the base of the exponential model change? d) Graph the new function from part c). What are the domain and range of this function?

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