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Match each function with the corresponding transformation of \(y=\left(\frac{3}{5}\right)^{x}\). a) \(y=\left(\frac{3}{5}\right)^{x+1}\) b) \(y=-\left(\frac{3}{5}\right)^{x}\) c) \(y=\left(\frac{3}{5}\right)^{-x}\) d) \(y=\left(\frac{3}{5}\right)^{x}-2\) \(\mathbf{A}\) reflection in the \(x\) -axis \(\mathbf{B}\) reflection in the \(y\) -axis \(\mathbf{C}\) translation down \(\mathbf{D}\) translation left

Short Answer

Expert verified
a) D, b) A, c) B, d) C

Step by step solution

01

Identify Base Function

The base function given is \( y = \left(\frac{3}{5}\right)^{x} \). This will be used for comparison with other functions.
02

Analyze Transformation for y = \left(\frac{3}{5}\right)^{x+1}

Adding 1 to the exponent (\(x+1\)) shifts the graph horizontally. Specifically, it results in a leftward translation because the function \( y = \left(\frac{3}{5}\right)^{x + k} \) moves left if \( k > 0 \). Thus, this corresponds to a translation left.
03

Analyze Transformation for y = -\left(\frac{3}{5}\right)^{x}

The negative sign in front of the function indicates a reflection over the x-axis. The graph of \( y = - f(x) \) is a reflection of \( y = f(x) \) over the x-axis.
04

Analyze Transformation for y = \left(\frac{3}{5}\right)^{-x}

Changing the sign of the exponent (to \(-x\)) flips the graph horizontally, indicating a reflection over the y-axis. The function \( y = f(-x) \) reflects \( y = f(x) \) over the y-axis.
05

Analyze Transformation for y = \left(\frac{3}{5}\right)^{x}-2

Subtracting 2 from the function translates the graph downward by 2 units. The function \( y = f(x) - k \) translates the graph downward if \( k > 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

horizontal translation
When you see a transformation like \( y = \left( \frac{3}{5} \right)^{x+1} \), the crucial detail is the addition inside the exponent. Horizontal translations involve shifts left or right along the x-axis.
In this case, adding 1 to the exponent of x (as in \( x + 1 \)) means moving the graph to the left by 1 unit.
Remember, shifts to the left occur when you add a positive number to x within the function:
  • If you see \( y = f(x+a) \), the graph shifts left by 'a' units
  • If it's \( y = f(x-a) \), it goes right by 'a' units.
Horizontal shifts don't affect the shape or orientation of the graph, just its position along the x-axis.
vertical translation
Next, consider a transformation like \( y = \left( \frac{3}{5} \right)^{x} - 2 \). This is a vertical translation.
Subtraction of a number from the entire function moves the graph downward by that number of units.
Vertical translations involve shifts up or down along the y-axis:
  • \( y = f(x) - a \) means shifting down by 'a' units.
  • Conversely, \( y = f(x) + a \) means shifting up by 'a' units.
These shifts also don't distort the graph's shape, only its vertical position.
In this example, subtracting 2 indicates the entire graph moves down by 2 units.
reflection over x-axis
Now, let’s explore reflections, starting with reflections over the x-axis like \( y = - \left( \frac{3}{5} \right)^{x} \).
The negative sign in front of the function reflects the graph across the x-axis.
  • This means every point on the original graph is flipped to the opposite side of the x-axis.
  • For example, if the original function was above the x-axis, after the transformation, it will be below the x-axis.
Reflections over the x-axis change the values of y but leave the x-coordinates unchanged.
reflection over y-axis
Lastly, let's discuss reflections over the y-axis using \( y = \left( \frac{3}{5} \right)^{-x} \).
The negative sign in the exponent indicates a reflection across the y-axis.
Each point on the graph of the original function is flipped over to the opposite side of the y-axis.
The transformation can be understood by these points:
  • Reflections over the y-axis change the x-coordinates of the graph’s points but leave the y-values unchanged.
So, if a point (x, y) was on the original graph, after the reflection, the point becomes (-x, y).

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Most popular questions from this chapter

Money in a savings account earns compound interest at a rate of \(1.75 \%\) per year. The amount, \(A,\) of money in an account can be modelled by the exponential function \(A=P(1.0175)^{n}\) where \(P\) is the amount of money first deposited into the savings account and \(n\) is the number of years the money remains in the account. a) Graph this function using a value of \(P=\$ 1\) as the initial deposit. b) Approximately how long will it take for the deposit to triple in value? c) Does the amount of time it takes for a deposit to triple depend on the value of the initial deposit? Explain. d) In finance, the rule of 72 is a method of estimating an investment's doubling time when interest is compounded annually. The number 72 is divided by the annual interest rate to obtain the approximate number of years required for doubling. Use your graph and the rule of 72 to approximate the doubling time for this investment.

Describe the transformations that must be applied to the graph of each exponential function \(f(x)\) to obtain the transformed function. Write each transformed function in the form \(y=a(c)^{b(x-h)}+k\). a) \(f(x)=\left(\frac{1}{2}\right)^{x}, y=f(x-2)+1\) b) \(f(x)=5^{x}, y=-0.5 f(x-3)\) c) \(f(x)=\left(\frac{1}{4}\right)^{x}, y=-f(3 x)+1\) d) \(f(x)=4^{x}, y=2 f\left(-\frac{1}{3}(x-1)\right)-5\)

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