Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

State the period for each periodic function, in degrees and in radians. Sketch the graph of each function. a) \(y=\sin 4 \theta\) b) \(y=\cos \frac{1}{3} \theta\) c) \(y=\sin \frac{2}{3} x\) d) \(y=\cos 6 x\)

Short Answer

Expert verified
a) 90° or \(\frac{\pi}{2}\) radians, b) 1080° or 6\(\pi\) radians, c) 540° or 3\(\pi\) radians, d) 60° or \(\frac{\pi}{3}\) radians

Step by step solution

01

Determine the Period Formula for Sine and Cosine Functions

The period for the basic sine and cosine functions, \(y = \sin \theta\) and \(y = \cos \theta\), is \(360^{\circ}\) or \(2\pi\) radians. When the function is modified by a coefficient, the period changes. The general formula for the period of \(y = \sin (k\theta)\) or \(y = \cos (k\theta)\) is \(\frac{360^{\circ}}{k}\) in degrees or \(\frac{2\pi}{k}\) in radians.
02

Calculate the Period for Function a

Given \(y = \sin 4\theta\), the coefficient \(k = 4\). Using the formula: \[\text{Period} = \frac{360^{\circ}}{4} = 90^{\circ}\] \[\text{Period} = \frac{2\pi}{4} = \frac{\pi}{2} \text{radians}\]
03

Calculate the Period for Function b

Given \(y = \cos \frac{1}{3}\theta\), the coefficient \(k = \frac{1}{3}\). Using the formula: \[\text{Period} = \frac{360^{\circ}}{\frac{1}{3}} = 1080^{\circ}\] \[\text{Period} = \frac{2\pi}{\frac{1}{3}} = 6\pi \text{radians}\]
04

Calculate the Period for Function c

Given \(y = \sin \frac{2}{3}x\), the coefficient \(k = \frac{2}{3}\). Using the formula: \[\text{Period} = \frac{360^{\circ}}{\frac{2}{3}} = 540^{\circ}\] \[\text{Period} = \frac{2\pi}{\frac{2}{3}} = 3\pi \text{radians}\]
05

Calculate the Period for Function d

Given \(y = \cos 6x\), the coefficient \(k = 6\). Using the formula: \[\text{Period} = \frac{360^{\circ}}{6} = 60^{\circ}\] \[\text{Period} = \frac{2\pi}{6} = \frac{\pi}{3} \text{radians}\]
06

Sketch Graphs of Each Function

For each function: (a) Sketch one complete cycle from 0 to the calculated period for \(y = \sin 4\theta\). (b) Sketch one complete cycle from 0 to the calculated period for \(y = \cos \frac{1}{3}\theta\). (c) Sketch one complete cycle from 0 to the calculated period for \(y = \sin \frac{2}{3}x\). (d) Sketch one complete cycle from 0 to the calculated period for \(y = \cos 6x\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sine function period
In trigonometry, the sine function, represented as \( \sin \theta \), is a periodic function. A periodic function repeats its values in regular intervals or periods. The period of the basic sine function \( y = \sin \theta \) is \( 360^{\circ} \) or \( 2\pi \) radians. When the sine function is modified by a coefficient like \( k \) in \( y = \sin (k\theta) \), the period is recalculated using the formula: \(\text{Period} = \frac{360^{\circ}}{k}\) in degrees or \(\text{Period} = \frac{2\pi}{k}\) in radians. For example, in the function \( y = \sin 4\theta \), the coefficient \( k = 4 \). Applying our formula we get: \(\text{Period} = \frac{360^{\circ}}{4} = 90^{\circ}\) in degrees and \(\frac{2\pi}{4} = \frac{\pi}{2} \) in radians. This means the function repeats every \( 90^{\circ} \) or \( \frac{\pi}{2} \) radians.
cosine function period
Like the sine function, the cosine function \( \cos \theta \) is also periodic. The basic cosine function \( y = \cos \theta \) has a period of \( 360^{\circ} \) or \( 2\pi \) radians. When the cosine function includes a coefficient \( k \), such as in \( y = \cos (k\theta) \), its period changes based on the same formulas used for the sine function: \(\text{Period} = \frac{360^{\circ}}{k}\) in degrees or \(\text{Period} = \frac{2\pi}{k}\) in radians. In the example \( y = \cos \frac{1}{3}\theta \), the coefficient \( k = \frac{1}{3} \), which changes the period to: \(\text{Period} = \frac{360^{\circ}}{\frac{1}{3}} = 1080^{\circ}\) in degrees and \(\frac{2\pi}{\frac{1}{3}} = 6\pi \) in radians. This indicates that the function's cycle repeats every \( 1080^{\circ} \) or \( 6\pi \) radians.
graphing periodic functions
Graphing periodic functions involves plotting their values over one or more periods. For trigonometric functions like sine and cosine, graphs typically show oscillatory behavior. Let's consider the function \( y = \sin 4\theta \), which has a period of \( 90^{\circ} \) or \( \frac{\pi}{2} \) radians. To graph this function:
  • Start from \( 0 \) and plot points for \( \theta \) values within one period, up to \( 90^{\circ} \) or \( \frac{\pi}{2} \) radians.

  • The sine function starts at \( 0 \), reaches a maximum at \( \frac{\pi}{4} \), returns to \( 0 \) at \( \frac{\pi}{2} \), and continues to oscillate.

Similarly, for the function \( y = \cos \frac{1}{3}\theta \), having a period of \( 1080^{\circ} \) or \( 6\pi \) radians, plot points from \( 0 \) to beyond a complete cycle to see the cosine curve oscillate. Remember, in each cycle both functions repeat their distinctive, wave-like patterns.
period calculation
Calculating the period of a sine or cosine function involves identifying and applying the coefficient \( k \). If you have a function \( y = \sin (k\theta) \) or \( y = \cos (k\theta) \), here’s what you do:
  • Extract the coefficient \( k \).

  • Apply the formula for the period in degrees: \(\text{Period} = \frac{360^{\circ}}{k}\).

  • For radians, use: \(\text{Period} = \frac{2\pi}{k}\).

For instance, consider \( y = \sin \frac{2}{3}x \). Here \( k = \frac{2}{3} \). Using the formula, we get: \(\text{Period} = \frac{360^{\circ}}{\frac{2}{3}} = 540^{\circ}\) in degrees and \(\frac{2\pi}{\frac{2}{3}} = 3\pi\) in radians. The function repeats every \( 540^{\circ} \) or \( 3\pi \) radians, respectively. This demonstrates the importance of correctly identifying \( k \) and applying the period formulas.
radians and degrees
Radians and degrees are two units to measure angles. Degrees are more commonly used in everyday settings, while radians are often used in advanced mathematics and physics.
  • One complete revolution around a circle is \( 360^{\circ} \).

  • In radians, the same revolution is \( 2\pi \).

Converting between them is simple: \(\text{Degrees} = \frac{180}{\pi} \times \text{Radians}\) and \(\text{Radians} = \frac{\pi}{180} \times \text{Degrees}\). For example, \( 180^{\circ} \) is \( \pi \) radians because \(\text{Radians} = \frac{\pi}{180} \times 180 = \pi\). When dealing with periodic functions, understanding both units allows you to plot graphs and find periods accurately. For instance, \( y = \cos 6x \) has \( k = 6 \). The period in degrees: \(\text{Period} = \frac{360^{\circ}}{6} = 60^{\circ}\), and in radians: \(\frac{2\pi}{6} = \frac{\pi}{3}\). Thus, the function repeats every \( 60^{\circ} \) or \( \frac{\pi}{3} \) radians.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The piston engine is the most commonly used engine in the world. The height of the piston over time can be modelled by a sine curve. Given the equation for a sine curve, \(y=a \sin b(x-c)+d,\) which parameter(s) would be affected as the piston moves faster?

Sketch one cycle of a sinusoidal curve with the given amplitude and period and passing through the given point. a) amplitude \(2,\) period \(180^{\circ},\) point (0,0) b) amplitude \(1.5,\) period \(540^{\circ},\) point (0,0)

The typical voltage, \(V\), in volts (V), supplied by an electrical outlet in Cuba is a sinusoidal function that oscillates between \(-155 \mathrm{V}\) and \(+155 \mathrm{V}\) and makes 60 complete cycles each second. Determine an equation for the voltage as a function of time, \(t.\)

a) State the five key points for \(y=\sin x\) that occur in one complete cycle from \(\mathbf{0}\) to \(2 \boldsymbol{\pi}\) b) Use the key points to sketch the graph of \(y=\sin x\) for \(-2 \pi \leq x \leq 2 \pi .\) Indicate the key points on your graph. c) What are the \(x\) -intercepts of the graph? d) What is the \(y\) -intercept of the graph? e) What is the maximum value of the graph? the minimum value?

State a possible domain and range for the given functions, which represent real-world applications. a) The population of a lakeside town with large numbers of seasonal residents is modelled by the function \(P(t)=6000 \sin (t-8)+8000.\) b) The height of the tide on a given day can be modelled using the function \(h(t)=6 \sin (t-5)+7\) c) The height above the ground of a rider on a Ferris wheel can be modelled by \(h(t)=6 \sin 3(t-30)+12.\) d) The average daily temperature may be modelled by the function \(h(t)=9 \cos \frac{2 \pi}{365}(t-200)+14.\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free