Chapter 5: Problem 4
State the amplitude of each periodic function. Sketch the graph of each function. a) \(y=2 \sin \theta\) b) \(y=\frac{1}{2} \cos \theta\) c) \(y=-\frac{1}{3} \sin x\) d) \(y=-6 \cos x\)
Short Answer
Expert verified
a) Amplitude = 2 b) Amplitude = \frac{1}{2}\ c) Amplitude = \frac{1}{3}\ d) Amplitude = 6
Step by step solution
01
- Identify the amplitude
The amplitude of a periodic function of the form \(y = A \sin \theta\) or \(y = A \cos \theta\) is the absolute value of the coefficient A. This tells us the maximum distance from the midline to the peak of the wave.
02
- Amplitude of each function
a) For \(y = 2 \sin \theta\), the coefficient A is 2. Thus, the amplitude is \[ |2| = 2 \] b) For \(y = \frac{1}{2} \cos \theta\), the coefficient A is \frac{1}{2}\. Thus, the amplitude is \[ |\frac{1}{2}| = \frac{1}{2} \] c) For \(y = -\frac{1}{3} \sin x\), the coefficient A is -\frac{1}{3}\. Thus, the amplitude is \[ |\frac{1}{3}| = \frac{1}{3} \] d) For \(y = -6 \cos x\), the coefficient A is -6. Thus, the amplitude is \[ |6| = 6 \]
03
- Sketch each graph
To sketch the graph: \ 1. For \(y = 2 \sin \theta\), draw a sine wave with peaks at 2 and troughs at -2. 2. For \(y = \frac{1}{2} \cos \theta\), draw a cosine wave with peaks at \frac{1}{2}\ and troughs at -\frac{1}{2}\. 3. For \(y = -\frac{1}{3} \sin x\), draw a sine wave reflected over the x-axis with peaks at -\frac{1}{3}\ and troughs at \frac{1}{3}\. 4. For \(y = -6 \cos x\), draw a cosine wave reflected over the x-axis with peaks at -6 and troughs at 6.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sin Function
The sine function, represented as \(y = \sin \theta\), is a fundamental periodic function. It's widely used in trigonometry and represented by a wave-like pattern. The sine function oscillates between -1 and 1. One full cycle of \(\sin \theta\) occurs over an interval of \[0, 2\pi \] on the x-axis. Key points to note:
- At \theta = 0\, the function starts at 0.
- It reaches its maximum value of 1 at \theta = \frac{\text{\pi}}{2}\.
- It returns to 0 at \theta = \pi\.
- It hits its minimum value of -1 at \theta = \frac{3\text{\pi}}{2}\.
- Completes the cycle back at 0 when \theta = 2\pi\.
Cos Function
The cosine function, denoted as \(y = \cos \theta\), is another core periodic function in trigonometry. It has a similar wave-like appearance but starts at a maximum value. The cosine function also moves between -1 and 1. Over an interval of \[0, 2\pi \], the key points are:
- At \theta = 0\, the function begins at 1.
- It goes down to 0 at \theta = \frac{\text{\pi}}{2}\.
- It reaches -1 at \theta = \pi\.
- It moves back up to 0 at \theta = \frac{3\text{\pi}}{2}\.
- Finally, it returns to 1 at \theta = 2\pi\.
Graphing Periodic Functions
To graph periodic functions like \(y = \sin \theta\) or \(y = \cos \theta\), follow these steps:
- Identify the amplitude from the coefficient \(A\). This defines the maximum value the graph reaches from its midline.
- Determine the period of the function. For \(\sin \theta\) and \(\cos \theta\), the period is \2\pi\.
- Find key points, such as maximums, minimums, and points where the function crosses the midline (usually at 0).
- Plot these points accurately on your graph.
- Connect the points smoothly to form the characteristic wave shape.
- If the coefficient is negative, reflect the graph over the x-axis. For example, with \(y= -\cos \theta\), peaks become troughs and vice versa.
Absolute Value of Coefficient
The absolute value of a coefficient in functions like \(y = A \sin \theta\) or \(y = A \cos \theta\) is critical for determining the amplitude. Amplitude is the height of the wave from the midline to the peak. Here's how to find it:
- Take the coefficient \(A\) in front of \sin\ or \cos\.
- Calculate its absolute value, represented as \|A|\. This removes any negative sign, ensuring the amplitude is positive.
- In \(y = 2 \sin \theta\), the amplitude is \|2| = 2\.
- In \(y = -6 \cos x\), the amplitude is \|6| = 6\.