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Sketch the graph of the curve that results after applying each transformation to the graph of the function \(f(x)=\sin x\). a) \(f\left(x-\frac{\pi}{3}\right)\) b) \(f\left(x+\frac{\pi}{4}\right)\) c) \(f(x)+3\) d) \(f(x)-4\)

Short Answer

Expert verified
Horizontally shift by \( \frac{\pi }{3} \) right and \( \frac{\pi }{4} \) left, then vertically shift by 3 units up and 4 units down.

Step by step solution

01

Identify the Base Function

The base function is given as \(f(x) = \sin x\). This is a standard sine function which oscillates between -1 and 1 with a period of \(2\pi\).
02

Apply Horizontal Shift for Part (a)

For \(f\left(x-\frac{\pi}{3}\right)\), the function is horizontally shifted to the right by \(\frac{\pi}{3}\). This transformation does not affect the amplitude or the period of the function.
03

Apply Horizontal Shift for Part (b)

For \(f\left(x+\frac{\pi}{4}\right)\), the function is horizontally shifted to the left by \(\frac{\pi}{4}\). Again, the amplitude and the period remain the same.
04

Apply Vertical Shift for Part (c)

For \(f(x)+3\), the entire function is shifted vertically upwards by 3 units. The new maximum value becomes 4 and the minimum value becomes 2.
05

Apply Vertical Shift for Part (d)

For \(f(x)-4\), the entire function is shifted vertically downwards by 4 units. The new maximum value becomes -3 and the minimum value becomes -5.
06

Combine Information for Sketching

Using the shifts described above, sketch the graphs of each transformed function. Ensure the horizontal shifts for (a) and (b) and the vertical shifts for (c) and (d) are accurately represented on the graph.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sine Function
Let's start with the basics. The sine function is written as \( f(x) = \sin x \), and it is one of the fundamental trigonometric functions. This function produces a smooth, wave-like pattern that oscillates between -1 and 1. The zeros of the sine function occur at multiples of \pi (0, \pi, 2\pi, ...) -------- signifying the points where the curve crosses the x-axis.
This function is periodic, meaning it repeats its pattern every \( 2\pi \) units. This repeating pattern is what gives trigonometric functions their unique properties. The sine function starts at zero, rises to a maximum value of 1, falls back to zero, decreases to a minimum value of -1, and finally returns to zero to complete one full cycle.

Due to its simple yet flexible form, the sine function is often used as the base function for various transformations, including horizontal shifts, vertical shifts, and more complex modifications. Understanding the basic properties of the sine function helps greatly in graph transformations.
Horizontal Shift
A horizontal shift involves moving the entire function left or right along the x-axis. In our examples, we have two horizontal shifts to consider:
When we shift the function to the right, as in \( f\left( x - \frac{ \pi }{ 3 } \right) \), we move each point on the graph right by \( \frac{ \pi }{ 3 } \) units. This doesn't change the function's amplitude (height) or period (distance required for one complete cycle). Only the position of the sine curve on the x-axis is modified. Essentially, this transformation means that peaks, troughs, and zeros of the sine curve will occur later than they used to.

For a left shift, such as \( f\left( x + \frac{ \pi }{ 4 } \right) \), each point on the original graph is moved to the left by \( \frac{ \pi }{ 4 } \) units. This also maintains the amplitude and period but shifts features like peaks and valleys to the left.

In both cases, it's crucial to note that the shape of the sine wave remains unchanged. Only its horizontal positioning is altered.
Vertical Shift
In contrast to horizontal shifts, vertical shifts involve moving the graph up or down along the y-axis. This is done by adding or subtracting a constant value from the sine function. Let’s see how we deal with this:
For an upward shift, like \( f(x) + 3 \), we move every point on the graph up by 3 units. This affects both the maximum and minimum values of the function. The peak of the sine wave, originally at 1, moves to 4, and the trough, originally at -1, shifts to 2. Essentially, we add 3 to every y-coordinate on the graph.

On the other hand, a downward shift, such as \( f(x) - 4 \), moves every point down by 4 units. This results in new maximum and minimum values of -3 and -5, respectively. Similar to the upward shift, we subtract 4 from every y-coordinate on the graph.

These vertical shifts affect where the sine function oscillates around the y-axis but don't change the period or the shape of the sine wave.
Periodic Functions
A key property of the sine function is that it's a periodic function. This means it repeats its pattern at regular intervals. For the sine function, this interval is \( 2\pi \). Every \( 2\pi \) units along the x-axis, the sine function completes one full cycle and starts anew.
This periodic nature is what gives the sine function and other trigonometric functions their oscillating wave forms. Periodic functions are essential in various applications, from signal processing to describing wave phenomena in physics.

When we apply transformations like horizontal and vertical shifts, we modify where each cycle of the function starts and ends or moves the entire wave up or down. Yet the periodic nature remains unaltered unless explicitly changed (e.g., by altering the function's frequency). Understanding periodicity helps predict and analyze wave patterns and transformations.

In summary, the sine function's periodicity, combined with horizontal and vertical shifts, creates a versatile tool for modeling and understanding wave-like behaviors in different contexts.

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Most popular questions from this chapter

Victor and Stewart determined the phase shift for the function \(f(x)=4 \sin (2 x-6)+12 .\) Victor said that the phase shift was 6 units to the right, while Stewart claimed it was 3 units to the right. a) Which student was correct? Explain your reasoning. b) Graph the function to verify your answer from part a).

After exercising for 5 min, a person has a respiratory cycle for which the rate of air flow, \(r,\) in litres per second, in the lungs is approximated by \(r=1.75 \sin \frac{\pi}{2} t,\) where \(t\) is the time, in seconds. a) Determine the time for one full respiratory cycle. b) Determine the number of cycles per minute. c) Sketch the graph of the rate of air flow function. d) Determine the rate of air flow at a time of 30 s. Interpret this answer in the context of the respiratory cycle. e) Determine the rate of air flow at a time of 7.5 s. Interpret this answer in the context of the respiratory cycle.

Write the equation of the sine function in the form \(y=a \sin b(x-c)+d\) given its characteristics. a) amplitude \(4,\) period \(\pi,\) phase shift \(\frac{\pi}{2}\) to the right, vertical displacement 6 units down b) amplitude 0.5, period \(4 \pi,\) phase shift \(\frac{\pi}{6}\) to the left, vertical displacement 1 unit up c) amplitude \(\frac{3}{4},\) period \(720^{\circ},\) no phase shift, vertical displacement 5 units down

Sketch one cycle of a sinusoidal curve with the given amplitude and period and passing through the given point. a) amplitude \(2,\) period \(180^{\circ},\) point (0,0) b) amplitude \(1.5,\) period \(540^{\circ},\) point (0,0)

A trick from Victorian times was to listen to the pitch of a fly's buzz, reproduce the musical note on the piano, and say how many times the fly's wings had flapped in 1 s. If the fly's wings flap 200 times in one second, determine the period of the musical note.

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