Chapter 29: Problem 665
Find the values of the trigonometric functions of an angle of \(-510^{\circ}\).
Short Answer
Expert verified
The values of the trigonometric functions for an angle of -510 degrees are:
\(\sin(-510^{\circ}) = -\frac{1}{2}\)
\(\cos(-510^{\circ}) = -\frac{\sqrt{3}}{2}\)
\(\tan(-510^{\circ}) = \frac{1}{\sqrt{3}}\)
\(\cot(-510^{\circ}) = \sqrt{3}\)
\(\sec(-510^{\circ}) = -\frac{2\sqrt{3}}{3}\)
\(\csc(-510^{\circ}) = -2\)
Step by step solution
01
Find the reference angle in the first rotation
To find the reference angle, we need to add or subtract multiples of 360 degrees until the angle is in the range of 0 to 360 degrees:
\(-510^{\circ}+360^{\circ} \times 2 = -510^{\circ}+720^{\circ}=210^{\circ}\)
So, the reference angle in the first rotation is 210 degrees.
02
Find the trigonometric functions values for the reference angle
Since 210 degrees is in the 3rd quadrant, we know that sine and cosine functions are negative and tangent function is positive in this quadrant. We can find the trigonometric functions values using the reference angle in the second quadrant (180 - 210 = -30 degrees):
\(\sin(-30^{\circ}) = -\frac{1}{2}\)
\(\cos(-30^{\circ}) = -\frac{\sqrt{3}}{2}\)
\(\tan(-30^{\circ}) = \frac{\sin(-30^{\circ})}{\cos(-30^{\circ})} = \frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}\)
03
Find the remaining trigonometric functions values
Using the trigonometric functions values found in Step 2, we can find the values of the other trigonometric functions:
\(\cot(-30^{\circ}) = \frac{1}{\tan(-30^{\circ})} = \frac{1}{\frac{1}{\sqrt{3}}} = \sqrt{3}\)
\(\sec(-30^{\circ}) = \frac{1}{\cos(-30^{\circ})} = \frac{2}{-\sqrt{3}} = -\frac{2\sqrt{3}}{3}\)
\(\csc(-30^{\circ}) = \frac{1}{\sin(-30^{\circ})} = \frac{1}{-\frac{1}{2}} = -2\)
04
Final Answer
The values of the trigonometric functions for an angle of -510 degrees are:
\[\sin(-510^{\circ}) = -\frac{1}{2}\]
\[\cos(-510^{\circ}) = -\frac{\sqrt{3}}{2}\]
\[\tan(-510^{\circ}) = \frac{1}{\sqrt{3}}\]
\[\cot(-510^{\circ}) = \sqrt{3}\]
\[\sec(-510^{\circ}) = -\frac{2\sqrt{3}}{3}\]
\[\csc(-510^{\circ}) = -2\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reference Angle
Understanding the reference angle is crucial in trigonometry when working with angles that are not within the first full circle (0 to 360 degrees). A reference angle is the positive acute angle that forms when the terminal side of the given angle meets the x-axis. This helps us simplify complex angles by using trigonometric identities established in the first quadrant.
To find the reference angle for \(-510^{\circ}\), we add multiples of \(360^{\circ}\) until it lies between \(0^{\circ}\) and \(360^{\circ}\). Here, we find:
To find the reference angle for \(-510^{\circ}\), we add multiples of \(360^{\circ}\) until it lies between \(0^{\circ}\) and \(360^{\circ}\). Here, we find:
- \(-510^{\circ} + 720^{\circ} = 210^{\circ}\)
Quadrants
The coordinate plane is divided into four sections, called quadrants, which help us determine the sign of trigonometric functions. Quadrants I through IV are arranged counter-clockwise:
- Quadrant I: All trigonometric functions are positive.
- Quadrant II: Sine is positive, cosine and tangent are negative.
- Quadrant III: Tangent is positive, sine and cosine are negative.
- Quadrant IV: Cosine is positive, sine and tangent are negative.
Sine
The sine (\(\sin\)) function represents the y-coordinate of the point on the unit circle corresponding to a given angle from the x-axis. In the context of our exercise:
- The reference angle is \(210^{\circ}\), which is the same as \(-30^{\circ} \) from the second quadrant's perspective.
- For \(\sin(-30^{\circ})\), it's known that it’s value is \(-\frac{1}{2}\).
Cosine
The cosine (\(\cos\)) function gives the x-coordinate of an angle's corresponding point on the unit circle. It helps us understand how far left or right the point is:
- For our problem, \(\cos(-30^{\circ})\) results in \(-\frac{\sqrt{3}}{2}\).
Tangent
The tangent (\(\tan\)) function is the ratio of the sine to the cosine of an angle. This is helpful since it combines insights from both functions.
- For \(\tan(-30^{\circ})\), we have \(\frac{\sin(-30^{\circ})}{\cos(-30^{\circ})} = \frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}\).