Chapter 15: Problem 316
Determine (a) the equation of lowest degree with rational coefficients, one of whose roots is \(\sqrt{13}-\sqrt{3}\); (b) the equation of lowest degree with real or complex coefficients having the roots 4 and \(4-9 \mathrm{i}\).
Short Answer
Expert verified
The short answers for both parts are:
(a) The equation of lowest degree with rational coefficients having the root \(\sqrt{13}-\sqrt{3}\) is:
\[P(x) = x^2 - 2\sqrt{13}x + 10\]
(b) The equation of lowest degree with real or complex coefficients having the roots 4 and \(4-9i\) is:
\[Q(x) = (x - 4)(x^2 - 8x + 97)\]
Step by step solution
01
Identify the root
Given root is \(\sqrt{13}-\sqrt{3}\).
02
Find the conjugate root
The conjugate of the given root is \(\sqrt{13}+\sqrt{3}\).
03
Write the equation
Let the polynomial equation be P(x). Since \(P(\sqrt{13}-\sqrt{3}) = 0\) and \(P(\sqrt{13}+\sqrt{3}) = 0\), we can write the equation as:
\[P(x) = (x - (\sqrt{13}-\sqrt{3}))(x - (\sqrt{13}+\sqrt{3}))\]
04
Simplify the equation
Now, multiply the factors to get the polynomial equation:
\begin{align*}
P(x) &= (x - (\sqrt{13}-\sqrt{3}))(x - (\sqrt{13}+\sqrt{3})) \\
&= (x - \sqrt{13} + \sqrt{3})(x - \sqrt{13} - \sqrt{3}) \\
&= x^2 - \sqrt{13}x - \sqrt{3}x + \sqrt{13}x + 13 + \sqrt{39} + \sqrt{3}x - \sqrt{39} - 3 \\
&= x^2 - 2\sqrt{13}x + 10.
\end{align*}
So, the equation of lowest degree with rational coefficients having the root \(\sqrt{13}-\sqrt{3}\) is:
\[P(x) = x^2 - 2\sqrt{13}x + 10\]
### Part (b) ###
05
Identify the roots
Given roots are 4 and \(4-9i\).
06
Find the conjugate root
The conjugate of the given complex root is \(4+9i\).
07
Write the equation
Let the polynomial equation be Q(x). Since \(Q(4) = 0\), \(Q(4-9i) = 0\), and \(Q(4+9i) = 0\), we can write the equation as:
\[Q(x) = (x - 4)(x - (4-9i))(x - (4+9i))\]
08
Simplify the equation
First, multiply the complex factors and then the real factor to get the polynomial equation:
\begin{align*}
Q(x) &= (x - 4)(x - (4-9i))(x - (4+9i)) \\
&= (x - 4) [(x - 4 + 9i)(x - 4 - 9i)] \\
&= (x - 4)(x^2 - 8x + 16 + 81) \\
&= (x - 4)(x^2 - 8x + 97).
\end{align*}
So, the equation of lowest degree with real or complex coefficients having the roots 4 and \(4-9i\) is:
\[Q(x) = (x - 4)(x^2 - 8x + 97)\]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conjugate Roots
When you deal with polynomial equations, especially with non-real numbers, understanding the concept of conjugate roots is crucial. In mathematics, when a polynomial has rational coefficients, and a non-real complex root is present, its conjugate pair must also appear as a root. This is essential because it keeps the polynomial equation's coefficients rational.
Let's consider two cases:
Hence, understanding and using the conjugate roots is necessary for constructing accurate polynomial equations that include complex or irrational roots.
Let's consider two cases:
- If you have a complex root like \( a + bi \), its conjugate would be \( a - bi \).
- If the root is given by square roots of irrational numbers such as \( \sqrt{m} - \sqrt{n} \), its conjugate will be \( \sqrt{m} + \sqrt{n} \).
Hence, understanding and using the conjugate roots is necessary for constructing accurate polynomial equations that include complex or irrational roots.
Complex Numbers
In mathematics, complex numbers are a category of numbers that extend the concept of one-dimensional number lines to a two-dimensional number plane. A complex number is defined in the form \( a + bi \), where \( a \) is the real part and \( bi \) is the imaginary part with \( i \) representing \( \sqrt{-1} \). Complex numbers are fundamental in solving equations that do not have real solutions.
They are vital in constructing polynomials with certain properties, like specified roots. Here's why they matter:
They are vital in constructing polynomials with certain properties, like specified roots. Here's why they matter:
- Enable the resolution of equations that fail to yield real solutions.
- Allow examination of systems and phenomena in fields such as engineering and physics, where real-only numbers are insufficient.
- Facilitate the computation of polynomials by ensuring the principle of conjugate pairs, as seen in our example, where if a polynomial has a complex root, its conjugate must also be included to keep coefficients rational.
Rational Coefficients
Rational coefficients are coefficients in polynomial equations that are rational numbers, meaning they can be expressed as fractions of integers. When creating polynomial equations from given roots, it's crucial to ensure that the coefficients remain rational if specified. For a polynomial equation like \( P(x) \) or \( Q(x) \), rational coefficients guarantee that the polynomial has a consistent and predictable form, especially important when there are irrational or complex roots.
Why are rational coefficients essential?
Why are rational coefficients essential?
- They ensure the polynomial has a real representation, even when dealing with non-real roots.
- They maintain uniformity for polynomials derived from real-world applications, where irrational coefficients are often not feasible.
- They align with the mathematical tradition, simplifying calculation and theory.