Question

Write the inequality and graph to show that temperature at which neon is a gas. “Neon the lowest temperature at which neon is a gas, called its boiling point $-411°F$”

Short answer

The temperature at which neon is a gas is $t\ge -411°F$.

Step-by-step solution

Step -1 - Apply the concept of Linear inequalities

In this type of question, Simply use the concept of understanding the question very carefully and then taking a variableand with accurate symbol >,< make a suitable inequality.

Step -2 – Finding the inequality by explaining the statement

Since, the statement is Neon the lowest temperature at which neon is a gas, called its boiling point $-411°F$.

From the above statement it is clearly seen that Neon is a gas at temperature higher than $-411°F$ and also a lowest temperature at which it is a gas.

Step- 3 – Make the expression of the inequality

Now, assume that t is the temperature where neon is a gas.

Hence, the inequality of the statement is $t\ge -411°F$.

Graphical Interpretation

Following is the graph of the expression $t\ge -411°F$ to get the proper graphical representation to know the points.

Here, the value of t is greater than or equal to $-411°F$.