Question

Find the lesser of the points of two coordinates such that A point on a coordinate plane is $3$ units from the x- axis and$4$ units from the y- axis. The point is in Quadrant II.

Short answer

The point be$(-4,3)$and located below:

Step-by-step solution

Step 1.  Apply the concept of QUADRANTS 

In this type of question, use the concept of various quadrants of the graph such that in second quadrant x coordinate is negative and y coordinate is positive

Step 2.  Finding the coordinate of the points.

Since, theDistance from x axis is given = $3$units.

And Distance from y axis is given =$4$units.

The quadrant of the point is given = Quadrant II.

Then, it is clearly that the coordinate of x is negative and y be positive in quadrant II.

So, The points be$(-4,3)$.

Graphical Representation:

Since, the point which is located in the graph is$(-4,3)$and also the points is in second quadrant. So, the graph shows the perfect identification of the points.