Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Using the given information and the fact that x and y are integers, tell whether the sum x + y is even or odd. Explain your reasoning.

x and y are odd.

Short Answer

Expert verified

If x and y are two odd integers, then their sum is always an even integer.

Step by step solution

01

Step 1. Definition of even and odd numbers.

An even number is a number that can be divided into two equal groups. Even numbers end in 2, 4, 6, 8 and 0 regardless of how many digits they have.

An odd number is a number that cannot be divided into two equal groups.

Examples of odd numbers are 3 , 5 , 7 , 9 , 11, ......

02

Rules for addition and subtraction of two even integers or odd integers 

1. An even number can only be formed by the sum of either 2 odd numbers (odd + odd = even), or 2 even numbers (even + even = even).

2. An odd number can only be formed by the sum of an odd and even number (odd + even = odd, or even + odd = odd).

03

Explanation for sum of two odd integers is even. 

The sum of two odd integers is always even.

Explanation:

Even numbers are always multiples of 2.

If x and y are two odd integers then there exists integers a, b such that x = 2a + 1 and y = 2b + 1.

x + y = 2a +1+ 2b + 1 = 2(a + b + 1). We can write x + y is always even.

Example: x = 15 and y = 21, then x + y = 15 + 21 = 36.

15, 21 are odd but the sum 36 is an even number.

Conclusion: Sum of two odd numbers is always an even number.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free