Question

Evaluate the expression when$r=4\text{\hspace{0.17em}and\hspace{0.17em}}s=6$.

${(r+1)}^2-s$

Short answer

The value of the expression is19.

Step-by-step solution

. Order of operations

To evaluate any expression involving more than one operation, follow the below order of operations:

• First evaluate expressions inside grouping symbols like parentheses ( ) or brackets [ ].
• Evaluate the exponents.
• Perform Multiplication and division from left to right.
• Perform addition and subtraction from left to right.

. Evaluate the expression inside parenthesis

To evaluate the expression${(r+1)}^2-s$ , substitute 4 for r and 6 for s in the expression and then simplify further by evaluating the expression in parenthesis as shown below,

$\begin{array}{c}{(r+1)}^2-s={(4+1)}^2-6\\ ={\left(5\right)}^2-6\\ =25-6\end{array}$

. Subtract the numbers

Now to simplify further, add the numbers to get

$\begin{array}{c}{(r+1)}^2-s=25-6\\ =19\end{array}$

Thus, the value of the expression is 19.