Question

Find the sum or difference.

$-\frac{3}{4}+\frac{1}{12}$

Short answer

$-\frac{2}{3}$

Step-by-step solution

Step 1. Given Information.

The provided expression is $-\frac{3}{4}+\frac{1}{12}$.

Step 2. Calculation.

Since, the denominators of the first and second fractions of the expression $-\frac{3}{4}+\frac{1}{12}$ are not the same, make the denominators common by multiplying the first fraction by $\frac{3}{3}$.

$-\frac{3}{4}\left(\frac{3}{3}\right)+\frac{1}{12}=-\frac{9}{12}+\frac{1}{12}$

Subtract the numerators of both obtained fractions to calculate the difference and simplify.

$\begin{array}{c}-\frac{9}{12}+\frac{1}{12}=\frac{-9+1}{12}\left[\text{writedifferenceofnumeratorsoverdenominator}\right]\\ -\frac{9}{12}+\frac{1}{12}=\frac{-8}{12}\left[\text{subtract}\right]\\ =-\frac{2}{3}\end{array}$

Step 3. Conclusion.

The difference is$-\frac{2}{3}$.