Chapter 2: Problem 3
Draw the direction field for the equation \(y^{\prime}=x^{2}+y^{2}\).
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 2: Problem 3
Draw the direction field for the equation \(y^{\prime}=x^{2}+y^{2}\).
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeBy the method of separation of variables solve \(y^{\prime}=(\cos x)(y-2)\) satisfying the initial condition \(y(0)=1\). Find the unique solution of the same equation satisfying \(y(0)=2 .\) Specify the interval on which the solution is defined in each case.
Solve the initial-value problem $$ \begin{aligned} y^{\prime} &=\alpha y-\beta y^{2}, \\ y(0) &=y_{0} \end{aligned} $$ where \(\alpha\) and \(\beta\) are small positive numbers. Show that $$ \lim _{x \rightarrow \infty} \phi(x)=\left\\{\begin{array}{ll} \alpha / \beta & \text { for } y_{0}>0, \\ 0 & \text { for } y_{0}=0 . \end{array}\right. $$ For \(y_{0}<0, \phi\) is unbounded as \(x\) approaches a certain value depending on \(y_{0}\).
A function is said to be periodic with period \(p\) if $$ f(x+n p)=f(x) $$ where \(n\) is an integer. Suppose that \(f(x)\) is continuous and periodic with period \(p\) for all \(x\). Show that if \(\phi(x)\) is a solution of the homogeneous equation $$ y^{\prime}+f(x) y=0 $$ then \(\phi(x+p)\) is also a solution. Show that for some constant \(c\), $$ \phi(x+p)=c \phi(x) $$ for all \(x\).
Show that a unique solution exists for each of the following initial-value problems. (a) $$ \begin{aligned} y^{\prime} &=x^{2}+y^{2} \\ y(0) &=0 \end{aligned} $$ on the interval \(|x|<\frac{1}{\sqrt{2}}\). (b) $$ y^{\prime}=1+y^{2} $$ $$ y(0)=0 $$ on the interval \(|x|<\frac{1}{2}\).
Solve the equation $$ y^{\prime}=1+y^{2} $$ satisfying \(y(0)=1 .\) Specify the interval on which the solution is defined.
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