Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Perform the indicated operation. Write all results in lowest terms. $$\frac{1}{4}+\frac{4}{9}-\frac{1}{9}$$

Short Answer

Expert verified
Question: Simplify the following expression: $$\frac{1}{4} + \frac{4}{9} - \frac{1}{9}$$ Answer: $$\frac{7}{12}$$

Step by step solution

01

Find the least common denominator (LCD) for the fractions

To find the LCD of the three fractions, we need to find the least common multiple (LCM) of their denominators. In this case, the denominators are 4 and 9. Both numbers are divisible by 1, so their LCM is 4 x 9 = 36.
02

Convert the fractions to equivalent fractions with the LCD

Now, we'll convert each fraction to an equivalent fraction with a denominator of 36: $$\frac{1}{4} = \frac{1 \times 9}{4 \times 9} = \frac{9}{36}$$ $$\frac{4}{9} = \frac{4 \times 4}{9 \times 4} = \frac{16}{36}$$ $$\frac{1}{9} = \frac{1 \times 4}{9 \times 4} = \frac{4}{36}$$
03

Perform the arithmetic operations

Now, we'll perform the addition and subtraction on the equivalent fractions: $$\frac{9}{36} + \frac{16}{36} - \frac{4}{36} = \frac{9 + 16 - 4}{36} = \frac{21}{36}$$
04

Simplify the resulting fraction

To simplify the fraction, we find the greatest common divisor (GCD) of the numerator and the denominator. The GCD of 21 and 36 is 3. So, we can divide both the numerator and the denominator by 3: $$\frac{21}{36} = \frac{21 \div 3}{36 \div 3} = \frac{7}{12}$$ The result of the expression is $$\frac{7}{12}$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free