Question

Six students purchase seven 5 -packs of report covers to distribute equally among themselves. a. Determine the total number of report covers to be distributed. b. How many report covers will each student receive? c. Set the calculation up as a long division and divide. d. Identify the divisor and the dividend. What is the quotient? What is the remainder, if any? e. Are there any report covers left over? f. Do this problem again using repeated subtraction.

Short answer

Answer: Each student receives 5 report covers, and there are 5 report covers left over.

Step-by-step solution

a. Determine the total number of report covers to be distributed.

First, we need to find the total number of report covers. Since there are seven 5-packs, we can simply multiply 7 by 5: 7 * 5 = 35 report covers.

b. How many report covers will each student receive?

Now, we need to divide the 35 report covers among the six students. To do this, we perform the division: 35 ÷ 6.

c. Set the calculation up as a long division and divide.

To set up long division, we write 35 inside the division symbol, and 6 outside: ____ 6 | 35 Now, we will perform the division step by step: 6 goes into 3 (3 ÷ 6) 0 times. Bring down the 5. 6 goes into 35 (35 ÷ 6) 5 times (5*6=30), with a remainder of 5. So, it looks like this: 5 R 5 ____ 6 | 35

d. Identify the divisor and the dividend. What is the quotient? What is the remainder, if any?

In our division problem (35 ÷ 6), the divisor is 6, the dividend is 35, the quotient is 5, and the remainder is 5.

e. Are there any report covers left over?

Yes, there are 5 report covers left over that couldn't be divided equally among the six students.

f. Do this problem again using repeated subtraction.

Using repeated subtraction, we subtract 6 (the number of students) from the total report covers (35) as many times as we can until we can't subtract anymore without going below 0. We keep track of how many times we subtract: 35 - 6 = 29 (1 subtraction) 29 - 6 = 23 (2 subtractions) 23 - 6 = 17 (3 subtractions) 17 - 6 = 11 (4 subtractions) 11 - 6 = 5 (5 subtractions) We performed 5 subtractions before we reached a number less than 6. So, each student will receive 5 report covers, with 5 report covers remaining (left over). This matches our previous long division result.