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Show by examples that all expressions \(\left(1^{*}\right)\) are indeterminate.

Short Answer

Expert verified
Expressions like \(1^{\infty}\) can lead to different outcomes, so they are indeterminate.

Step by step solution

01

Understand the concept of indeterminate forms

Indeterminate forms occur in calculus when evaluating limits leads to expressions that do not have a clear limit. The indeterminate form related to this exercise is \(1^*\), which can result in different outcomes based on the context of the expressions within limits.
02

Set up a simple function that leads to 1^*

Consider the function \( y = (1+\frac{1}{x})^x \). As \(x \to \infty\), this expression approaches the number \(e\), showcasing that \(1^{\infty}\) can lead to a finite number different from 1.
03

Choose another function leading to 1^* context

Let's examine the function \(y = (1+\frac{1}{x})^{-x} \). As \(x \to \infty\), the expression evaluates to \(e^{-1}\) or \(\frac{1}{e}\), demonstrating an indeterminate form different from 1.
04

Evaluate yet another example of 1^*

Take the function \(y = \left(1+\frac{1}{x}\right)^{x^2} \). As \(x \to \infty\), this expression approximates \(0\), highlighting further the indeterminate nature of \(1^{\infty}\) leading to a very different value from the previous examples.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits in Calculus
Limits are fundamental in calculus, providing a way to understand the behavior of functions as they approach certain points or infinity. When we say we are "taking a limit," we mean predicting the value that a function approaches as the input changes. For example, if we have a function \( f(x) \), and we are interested in what happens as \( x \) approaches a particular number \( a \), we explore \( \lim_{x \to a} f(x) \).
A limit can be finite, infinite, or it might not exist. Calculating limits involves algebraic manipulation and applying limit laws, such as the quotient, product, and power rules. Limits help evaluate expressions where direct substitution is not possible due to indeterminate forms, such as \( \frac{0}{0} \) or \( 1^* \). Exploring limits can unlock a deeper understanding of continuity, derivatives, and integrals, making them indispensable in calculus.
Exponential Functions
Exponential functions have the form \( f(x) = a^x \), where \( a \) is a constant and \( x \) is the exponent. They are essential in modeling growth and decay, featuring applications in science, finance, and mathematics. A key feature of exponential functions is their constant relative rate of growth or decay, meaning they increase or decrease by a fixed percentage over equal intervals.
In calculus, the natural exponential function \( e^x \) is particularly important. The number \( e \) is approximately 2.71828 and serves as the base of natural logarithms. It arises naturally in the context of rates of change and compounding processes.
Exponential functions exhibit unique properties:
  • \( e^x \) is its own derivative and integral.
  • \( e^0 = 1 \), establishing a useful point of reference.
  • Exponential functions can approach limits and help understand indeterminate forms like \( 1^{\infty} \).
Their graphical representation shows rapid growth or decay, depending on whether the exponent is positive or negative.
Indeterminate Form Examples
Indeterminate forms occur when evaluating the limit of a function leads to an expression that does not initially suggest a particular value. The most common examples include \( \frac{0}{0} \), \( 0 \times \infty \), \( \infty - \infty \), and \( 1^{\infty} \). Each has unique characteristics, requiring special techniques to resolve, such as L'Hôpital's Rule, algebraic simplification, or using series expansions.
In the context of \( 1^{\infty} \), this form is particularly intriguing because it suggests multiplying 1 by itself an infinite number of times, which implies 1. However, the specific function involved might lead to various results when approaching the limit, as shown by our examples:
  • \( y = (1 + \frac{1}{x})^x \to e \) as \( x \to \infty \), showcasing a convergence to Euler's number \( e \).
  • \( y = (1 + \frac{1}{x})^{-x} \to \frac{1}{e} \), which changes the limiting value simply by altering the exponent's sign.
  • \( y = (1+\frac{1}{x})^{x^2} \to 0 \), indicating how squared exponents alter the limit outcome entirely.
These examples showcase the flexibility and complexity of indeterminate forms, illustrating that context truly matters in the realm of limits and calculus.

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Most popular questions from this chapter

Let \(f_{n} \rightarrow f\) (uniformly) on \(B\). Prove the equivalence of the following statements: (i) Each \(f_{n}\), from a certain \(n\) onward, is bounded on \(B\). (ii) \(f\) is bounded on \(B\). (iii) The \(f_{n}\) are ultimately uniformly bounded on \(B ;\) that is, all function values \(f_{n}(x), x \in B,\) from a certain \(n=n_{0}\) onward, are in one and the same globe \(G_{q}(K)\) in the range space. For real, complex, and vector-valued functions, this means that $$ \left(\exists K \in E^{1}\right)\left(\forall n \geq n_{0}\right)(\forall x \in B) \quad\left|f_{n}(x)\right|

Show that each arc is a continuous image of [0,1] . [Hint: First, show that any \([a, b] \subseteq E^{1}\) is such an image. Then use a suitable composite mapping.]

In the following cases, find \(\lim f(x)\) in two ways: (i) use definitions only; (ii) use suitable theorems and justify each step accordingly. (a) \(\lim _{x \rightarrow \infty} \frac{1}{x}(=0)\). (b) \(\lim _{x \rightarrow \infty} \frac{x(x-1)}{1-3 x^{2}}\). (c) \(\lim _{x \rightarrow 2^{+}} \frac{x^{2}-2 x+1}{x^{2}-3 x+2}\). (d) \(\lim _{x \rightarrow 2^{-}} \frac{x^{2}-2 x+1}{x^{2}-3 x+2}\). (e) \(\lim _{x \rightarrow 2} \frac{x^{2}-2 x+1}{x^{2}-3 x+2}(=\infty)\).

Suppose that no two of the sets \(A_{i}(i \in I)\) are disjoint. Prove that if all \(A_{i}\) are connected, so is \(A=\bigcup_{i \in I} A_{i}\) [Hint: If not, let \(A=P \cup Q(P, Q\) as in Definition 3). Let \(P_{i}=A_{i} \cap P\) and \(Q_{i}=A_{i} \cap Q,\) so \(A_{i}=P_{i} \cup Q_{i}, i \in I\) That is, onto a two-point set \\{0\\}\(\cup\\{1\\}\). \S10. Arcs and Curves. Connected Sets At least one of the \(P_{i}, Q_{i}\) must be \(\emptyset\) (why?); say, \(Q_{j}=\emptyset\) for some \(j \in I\). Then \((\forall i) Q_{i}=\emptyset,\) for \(Q_{i} \neq \emptyset\) implies \(P_{i}=\emptyset,\) whence $$ A_{i}=Q_{i} \subseteq Q \Longrightarrow A_{i} \cap A_{j}=\emptyset\left(\text { since } A_{j} \subseteq P\right) $$ contrary to our assumption. Deduce that \(Q=\bigcup_{i} Q_{i}=\emptyset\). (Contradiction!)]

The functions \(f_{n}: A \rightarrow\left(T, \rho^{\prime}\right), A \subseteq(S, \rho)\) are said to be equicontinuous at \(p \in A\) iff $$ (\forall \varepsilon>0)(\exists \delta>0)(\forall n)\left(\forall x \in A \cap G_{p}(\delta)\right) \quad \rho^{\prime}\left(f_{n}(x), f_{n}(p)\right)<\varepsilon $$ Prove that if so, and if \(f_{n} \rightarrow f\) (pointwise) on \(A\), then \(f\) is continuous at \(p\).

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