Chapter 3: Problem 4
A set \(A\) in \((S, \rho)\) is said to be totally bounded iff for every \(\varepsilon>0\) (no matter how small \(), A\) is contained in a finite union of globes of radius \varepsilon. By Problem 3 , any such set is bounded. Disprove the converse by a counterexample. [Hint: Take an infinite set in a discrete space.]
Short Answer
Step by step solution
Understanding the Definitions
Identifying a Suitable Metric Space
Selecting an Infinite Set in the Discrete Space
Checking Boundedness of Set A
Disproving Total Boundedness
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Totally Bounded
For example, consider the set of rational numbers between 0 and 1. No matter how small the radius, you can always find a finite number of intervals to cover this set. It's like tucking a blanket around them regardless of how the temperature changes. But note, being totally bounded is a stricter condition than just being bounded. It means you can "bunch up" the set into these small covers completely and finitely.
Key points:
- Requires finite coverage with small radius.
- Stricter than mere boundedness.
Discrete Metric Space
This setup makes the concept of distance straightforward. In such a setting, every subset is both closed and open as each point essentially stands alone with respect to its neighbors. This distinct sharpness of distance helps make many problems about distance calculations easier.
It's worth noting that in such spaces, visualizing concepts like total boundedness or boundedness might differ compared to continuous spaces:
- Distinct points: distance 1.
- Same points: distance 0.
- Simplifies many distance complexities.
Bounded Sets
This concept doesn't consider the number of elements or size of the set, only if you can stop it from "stretching out" indefinitely. Even an infinite set can be called bounded if it fits snugly inside such a fence. But remember, being bounded doesn't necessarily make a set totally bounded, as seen in some infinite sets in discrete spaces.
Key attributes:
- Contained within a fixed distance.
- Doesn’t extend beyond a certain point.
- Can include infinite sets.
Infinite Sets
In metric spaces, infinite sets can still hold peculiar properties. For instance, in a discrete metric space, an infinite set can be bounded but not totally bounded. This seems paradoxical but highlights the importance of understanding different types of *boundedness*.
Attributes of infinite sets:
- No finite end.
- Common example: natural numbers.
- Can exemplify different boundedness properties.