Chapter 3: Problem 11
Give examples to show that an infinite intersection of open sets may not be open, and an infinite union of closed sets may not be closed. [Hint: Show that $$ \bigcap_{n=1}^{\infty}\left(-\frac{1}{n}, \frac{1}{n}\right)=\\{0\\} $$ and $$ \left.\bigcup_{n=2}^{\infty}\left[\frac{1}{n}, 1-\frac{1}{n}\right]=(0,1) .\right] $$
Short Answer
Step by step solution
Understanding Open Sets and Intersections
Solving the Intersection Example
Understanding Closed Sets and Unions
Solving the Union Example
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Open Sets
Open sets have an interesting interaction when intersected. If you take an infinite intersection of open sets, the result might not itself be open. For instance, consider the open interval (-1/n, 1/n) for each natural number n. As n grows, this interval squeezes towards the center. If you continue infinitely, the only remaining point common to all these intervals is the single point {0}. This resulting set {0} is not open because if it were, there would need to be some interval around it that lies entirely within an open set, which isn't possible as it contains a boundary point without an internal interval rich in points.
Closed Sets
When thinking about closed sets, an interesting case arises when you explore their infinite unions. Normally, closed sets are well-defined by the inclusion of their boundary points, but the union of infinitely many such sets does not guarantee closure. For example, taking the union of [1/n, 1 - 1/n] for n starting from 2 up to infinity, the union broadens enough to eventually capture every point in the open interval (0, 1). However, it does not include 0 or 1 because there is no single interval that has these endpoints. Thus, the infinite union results in an open interval (0, 1), showing that the infinite union of closed sets can sometimes be open.
Infinite Intersections
As n becomes exceedingly large, the intervals fast approach the single point 0. Thus, i.e., \(igcap_{n=1}^{ ext{∞}}(-1/n, 1/n) = \{0\}\). This is not open in the topological sense, since an open set must not include its boundary points, and 0 here lacks surrounding points to form an internal interval. Therefore, it's pivotal to note that the infinite intersection of open sets can collapse down to a non-open set, often just a point in such cases.
Infinite Unions
If we continue to take the union of many such intervals starting from n=2, we start packing more points within each subsequent interval. This sequential union spans further and further towards the boundaries of (0, 1). Eventually, the union captures nearly everything in (0, 1).
Significantly, this expansive union of closed intervals [1/n, 1-1/n] between n = 2 to ∞ do not converge to a closed set but rather an open interval \((0, 1)\). This example reveals how the infinite union of closed sets can deviate from closure by being unable to secure boundary points, showing how flexibility in one scenario does not always sustain in another when extending to "infinite" scenarios.