Chapter 2: Problem 8
Prove that if \(p=\lim x_{n}\) in \(E^{1}\), then $$\underline{\lim }\left(x_{n}+y_{n}\right)=p+\underline{\lim } y_{n} ;$$ similarly for \(\bar{L}\).
Short Answer
Expert verified
\(\underline{\lim} (x_n + y_n) = p + \underline{\lim} y_n;\ \overline{\lim} (x_n + y_n) = p + \overline{\lim} y_n.\)
Step by step solution
01
Understanding the Problem
We need to prove that for the sequence of real numbers, if the limit of \(x_n\) exists and is \(p\), then the limit inferior of the sequence \((x_n + y_n)\) is equal to \(p + \underline{\lim} y_n\), and similarly for the limit superior.
02
Recall Definitions
Recall that \( \underline{\lim} a_n = \lim_{n \to \infty} \inf_{k \geq n} a_k \) and \( \overline{\lim} a_n = \lim_{n \to \infty} \sup_{k \geq n} a_k \). These are the limit inferior and limit superior of a sequence.
03
Apply Limits and Properties for \(x_n\)
Given \(p = \lim x_n\), this implies \(x_n \to p\) as \(n \to \infty\). This means that for any \(\epsilon > 0\), there exists some \(N\) such that for all \(n > N\), \(|x_n - p| < \epsilon\).
04
Apply Limits to Combined Sequence
Consider the sequence \(x_n + y_n\). We know that \(\lim x_n = p\), so for \(n\) large enough, \(x_n + y_n\) behaves similar to \(p + y_n\).
05
Prove Limit Inferior Identity
For the limit inferior, we consider \(\underline{\lim} (x_n + y_n) = \lim_{n \to \infty} \inf_{k \ge n} (x_k + y_k)\). Because \(x_n\) approaches \(p\), we have \( (p + \inf_{k \ge n} y_k ) \) for large \(n\), which implies \( \underline{\lim} (x_n + y_n) = p + \underline{\lim} y_n\).
06
Prove Limit Superior Identity
Similarly, for the limit superior, we consider \(\overline{\lim} (x_n + y_n) = \lim_{n \to \infty} \sup_{k \ge n} (x_k + y_k)\). Because \(x_n\) approaches \(p\), this turns into \(p + \sup_{k \ge n} y_k\), leading to \(\overline{\lim} (x_n + y_n) = p + \overline{\lim} y_n\).
07
Conclusion of Proof
We have shown that both identities for limit inferior and limit superior hold: \( \underline{\lim} (x_n + y_n) = p + \underline{\lim} y_n \) and \( \overline{\lim} (x_n + y_n) = p + \overline{\lim} y_n \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Superior
The limit superior (often denoted as \( \overline{\lim} a_n \)) of a sequence is essentially a way to capture the largest value that the sequence approaches as \( n \to \infty \). This isn't necessarily the maximum value of the entire sequence, but rather the supremum (least upper bound) of all possible accumulation points.Think of it as the ceiling, or highest level, that the sequence keeps approaching, even if just for fleetingly short intervals. It is defined mathematically as:\[ \overline{\lim} a_n = \lim_{n \to \infty} \sup_{k \geq n} a_k \]Here is how it works:
- The expression \( \sup_{k \geq n} a_k \) calculates the smallest number that is greater than or equal to every \( a_k \) for \( k \geq n \).
- Taking the limit as \( n \rightarrow \infty \), we find the smallest ceiling towards which the tail of the sequence grows.
Limit Inferior
Limit inferior (denoted as \( \underline{\lim} a_n \)) provides us with a way to capture the smallest value that a sequence approaches as \( n \to \infty \). Just like limit superior, it's not necessarily the smallest element in the sequence, but rather the greatest lower bound of all the sequence's possible limit points.The formal definition is:\[ \underline{\lim} a_n = \lim_{n \to \infty} \inf_{k \geq n} a_k \]This can be explained in an approachable way:
- \( \inf_{k \geq n} a_k \) looks at the largest number \( a_k \) for \( k \geq n \), below which all subsequent terms \( a_k \) fall.
- By taking the limit as \( n \rightarrow \infty \), we find the highest floor that the tail end of the sequence can be said to consistently reach.
Convergent Sequences
A convergent sequence is one of the simplest concepts in mathematical analysis, yet incredibly important. A sequence \( \{x_n\} \) is said to converge if it approaches a single finite number \( p \) as \( n \to \infty \). In other words, the further along in the sequence you go, the closer the terms get to \( p \).This can be expressed formally:For every \( \epsilon > 0 \), there exists an \( N \) such that for all \( n > N \), \( |x_n - p| < \epsilon \).Breaking this down, we get:
- "For every \( \epsilon > 0\)" means no matter how small a margin of error we choose, the sequence will eventually show a consistent trend toward \( p \).
- Buying an "N" implies that beyond some point in the sequence \( N \), all terms of the sequence are inside the margin we've set.