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Show that between any real numbers \(a, b(a

Short Answer

Expert verified
Uncountably many irrationals exist between any two reals due to their dense and uncountable nature.

Step by step solution

01

Understanding the Problem

We need to demonstrate that there are more irrational numbers between any two real numbers, say \(a\) and \(b\), than there are rational numbers. This involves showing that irrationals are uncountably infinite in this interval.
02

Properties of the Real Number Line

The interval \((a, b)\) is a segment of the real number line which contains both rational and irrational numbers. According to the density property of real numbers, between any two distinct real numbers exists another irrational number. This fact hints towards the presence of irrationals in any interval on the real number line.
03

Rational and Irrational Numbers

Real numbers can be classified into rationals (numbers that can be expressed as fractions) and irrationals (numbers that cannot be expressed as such). While rational numbers are countable (like integers or natural numbers), irrational numbers are uncountable.
04

Density of Rational and Irrational Numbers

Both rational and irrational numbers are dense in the real numbers. This means for any two real numbers, say \(a\) and \(b\), there is an irrational number between them. Due to their uncountable nature, irrationals fill the interval densely and completely.
05

Cantor's Diagonal Argument for Uncountability

To show there are uncountably many irrationals, recall Cantor's diagonal argument. It illustrates that the set of real numbers is uncountable. Since irrationals contribute to this set significantly, we conclude there are uncountably many irrationals in any interval \((a, b)\).
06

Conclusion Applying the Argument

Since rational numbers are countable and irrationals are uncountable, in any interval \((a, b)\), there must be uncountably many irrational numbers. This conclusion is supported by their respective properties.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Uncountable Infinity
In mathematics, infinity isn't just a single concept; there are different sizes of infinity. When we talk about the idea of "uncountable infinity," we are referring to a particularly large type of infinity. To visualize this, consider the difference between counting natural numbers and thinking about the real numbers. While natural numbers (like 1, 2, 3) go on forever, you can still count them one by one. This makes them a "countable infinity."

However, the real numbers aren't just countable. They're more complex because between any two real numbers, there are infinitely many numbers that cannot be listed one by one. This forms an "uncountable infinity." It's like trying to count all the points on a line segment — they are so densely packed and continuous that listing them all is impossible. Thus, real numbers, which include both the rational and irrational numbers, are uncountably infinite.
Exploring Cantor's Diagonal Argument
Cantor's diagonal argument is a clever way to show that not all infinities are the same size. This argument specifically proves that the real numbers form an uncountable set, unlike natural numbers which are countable. Imagine trying to write a list of all real numbers between 0 and 1.

Every number can be represented by an infinite decimal. Cantor came up with a way to show a contradiction if you assume you could list every real number:
  • Construct a new number by changing each digit on the diagonal of your list.
  • If the first number's first digit is 3, make the new number's first digit a different number, like 4.
  • Repeat this down the diagonal).
This new number differs from every number on your list in at least one decimal place, proving that the assumption of listing all real numbers is impossible. The set of real numbers is therefore uncountable, highlighting the distinct nature of irrational numbers within them.
Understanding the Density of Real Numbers
The density of real numbers is a fundamental concept that enriches our understanding of the real number line. What does it mean for numbers to be "dense"? It means that between any two real numbers, you can always find another real number. This applies to both rational and irrational numbers.

For rational numbers, no matter how close two rational numbers are, there's always another one in between. This property is mirrored by irrational numbers. Between any two real numbers — regardless of how small the interval — there is always an irrational number present.
  • This is why we say that real numbers are dense: they fill every gap without leaving any holes.
  • Even if you take two numbers extremely close together, you'll still find more numbers nestled between them.
Thus, the density of real numbers, including irrationals, emphasizes the vastness of uncountability and illustrates how the real number line is seamlessly filled with irrational numbers.

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Most popular questions from this chapter

Prove Theorem 1 (show that \(x\) is in the left-hand set iff it is in the right- hand set). For example, for (d), $$ \begin{aligned} x \in(A \cup B) \cap C & \Longleftrightarrow[x \in(A \cup B) \text { and } x \in C] \\ & \Longleftrightarrow[(x \in A \text { or } x \in B), \text { and } x \in C] \\\ & \Longleftrightarrow[(x \in A, x \in C) \text { or }(x \in B, x \in C)]. \end{aligned} $$

Describe geometrically the following sets in the \(x y\) -plane. (i) \(\\{(x, y) \mid xx^{2}\right\\}\) (v) \(\\{(x, y)|| x|+| y \mid<4\\} ;\) (vi) \(\left\\{(x, y) \mid(x-2)^{2}+(y+5)^{2} \leq 9\right\\}\) (vii) \(\\{(x, y) \mid x=0\\} ;\) (viii) \(\left\\{(x, y) \mid x^{2}-2 x y+y^{2}<0\right\\} ;\) (ix) \(\left\\{(x, y) \mid x^{2}-2 x y+y^{2}=0\right\\}\).

Is \(R\) an equivalence relation on the set \(J\) of all integers, and, if so, what are the \(R\) -classes, if (a) \(R=\\{(x, y) \mid x-y\) is divisible by a fixed \(n\\}\) (b) \(R=\\{(x, y) \mid x-y\) is \(o d d\\}\) (c) \(R=\\{(x, y) \mid x-y\) is a prime \(\\}\). \((x, y, n\) denote integers.)

Let \(f\) be a mapping, and \(A \subseteq D_{f} .\) Prove that (i) if \(A\) is countable, so is \(f[A]\); (ii) if \(f\) is one to one and \(A\) is uncountable, so is \(f[A]\).

Let \((a, b)\) denote the set $$ \\{\\{a\\},\\{a, b\\}\\} $$ (Kuratowski's definition of an ordered pair). (i) Which of the following statements are true? (a) \(a \in(a, b)\); (b) \(\\{a\\} \in(a, b)\); (c) \((a, a)=\\{a\\}\); (d) \(b \in(a, b)\); (e) \(\\{b\\} \in(a, b)\); \((\mathrm{f})\\{a, b\\} \in(a, b)\); (ii) Prove that \((a, b)=(u, v)\) iff \(a=u\) and \(b=v\). [Hint: Consider separately the two cases \(a=b\) and \(a \neq b,\) noting that \(\\{a, a\\}=\) \(\\{a\\} .\) Also note that \(\\{a\\} \neq a .]\)

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