Chapter 3: Problem 4
Let \(\mathfrak{A}=\langle N,<\rangle, \mathfrak{B}=\langle N-\\{0\\},<\rangle .\) Show: \(\quad\) (i) \(\quad \mathbf{A} \cong \mathfrak{B}\); (ii) \(\mathfrak{a} \equiv \mathfrak{B}\); (iii) \(\mathfrak{B} \subseteq \mathfrak{A}\); (iv) \(\quad\) not\mathfrak \(\mathfrak{B} \prec \mathfrak{A}\).
Short Answer
Expert verified
(i) \( \mathfrak{A} \cong \mathfrak{B} \); (ii) \( \mathfrak{A} \equiv \mathfrak{B} \); (iii) \( \mathfrak{B} \subseteq \mathfrak{A} \); (iv) \( \mathfrak{B} \not\prec \mathfrak{A} \).
Step by step solution
01
Define the Structures
Let's first understand the structures. \( \mathfrak{A} = \langle N, < \rangle \) is the set of natural numbers with the usual order. \( \mathfrak{B} = \langle N - \{0\}, < \rangle \) is the set of positive natural numbers with the same order.
02
Show \( \mathfrak{A} \cong \mathfrak{B} \)
Two structures are isomorphic if there exists a bijection between their sets that preserves the ordering. Define the function \( f: N \to N - \{0\} \) by \( f(n) = n+1 \). This function is a bijection because it maps each natural number \( n \) to a unique element in \( N - \{0\} \), and it preserves order since \( n < m \Rightarrow f(n) = n+1 < m+1 = f(m) \). Thus, \( \mathfrak{A} \cong \mathfrak{B} \).
03
Show \( \mathfrak{A} \equiv \mathfrak{B} \)
Two structures are elementarily equivalent if they satisfy the same first-order properties. Since they are isomorphic as shown above, they must satisfy the same first-order sentences, hence \( \mathfrak{A} \equiv \mathfrak{B} \).
04
Show \( \mathfrak{B} \subseteq \mathfrak{A} \)
The set \( N - \{0\} \) is a subset of \( N \) by definition, because each element in \( N - \{0\} \) is a natural number greater than 0, which are elements of \( N \). Thus, \( \mathfrak{B} \subseteq \mathfrak{A} \).
05
Show \( \mathfrak{B} \not\prec \mathfrak{A} \)
For \( \mathfrak{B} \prec \mathfrak{A} \) to hold, every property true in \( \mathfrak{B} \) must be true in \( \mathfrak{A} \), but not vice versa. However, \( \mathfrak{A} \) contains all the elements of \( \mathfrak{B} \) plus 0, making \( \mathfrak{A} \equiv \mathfrak{B} \). Therefore, \( \mathfrak{B} ot\prec \mathfrak{A} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isomorphism
Isomorphism is a foundational concept in mathematical logic and model theory. Two structures, such as sets or groups, are considered isomorphic if they can be mapped onto each other by a bijection that respects their inherent structure and relations. In simpler words, if you can "relabel" one structure to get the other while preserving all relationships, they are isomorphic.
In our example, we have two structures:
In our example, we have two structures:
- \( \mathfrak{A} = \langle N, < \rangle \) is the set of all natural numbers with the usual order\( < \).
- \( \mathfrak{B} = \langle N - \{0\}, < \rangle \) represents the set of positive natural numbers, also ordered by the usual \( < \).
Elementary Equivalence
Elementary equivalence is about two structures satisfying the same set of first-order logic sentences, which are statements describing properties and relations. If two structures are elementarily equivalent, any property expressed in first-order logic that holds in one must hold in the other.
In the given problem, since \( \mathfrak{A} \) and \( \mathfrak{B} \) are shown to be isomorphic, they automatically satisfy the same first-order statements, and hence \( \mathfrak{A} \equiv \mathfrak{B} \).
This occurs because isomorphisms ensure not just a structural similarity but also a logical equivalence in terms of first-order logic. All properties that can be described without needing a second or higher order description are preserved. This is a crucial aspect of model theory, as it extends our understanding of how structures relate beyond just physical appearance to their logical and property-based behavior.
In the given problem, since \( \mathfrak{A} \) and \( \mathfrak{B} \) are shown to be isomorphic, they automatically satisfy the same first-order statements, and hence \( \mathfrak{A} \equiv \mathfrak{B} \).
This occurs because isomorphisms ensure not just a structural similarity but also a logical equivalence in terms of first-order logic. All properties that can be described without needing a second or higher order description are preserved. This is a crucial aspect of model theory, as it extends our understanding of how structures relate beyond just physical appearance to their logical and property-based behavior.
Model Theory
Model theory intersects logic and abstract algebra to study the relationships between formal languages (like that of first-order logic) and their interpretations or "models." A model here refers to a set equipped with additional structure, such as an order or operation, that satisfies a given theory or set of formulas.
In our example:
In our example:
- \( \mathfrak{A} \) and \( \mathfrak{B} \) serve as models of algebraic structures with the order relation.
- The concepts of isomorphism and elementary equivalence are special cases in model theory, exploring when different models of a theory are essentially the same or when they satisfy the same sentences.
Ordered Structures
Ordered structures, as seen in the exercise, involve sets with a defined order relationship. Ordered structures help extend our understanding of mathematics by bringing order into otherwise unordered sets, providing a way to handle sequences, limits, and continuity.
In this exercise,:
Understanding the order within these structures reveals deeper insights into how systems evolve, interact, and can be manipulated. Whether dealing with number systems, geometries, or other forms of data, ordered structures contribute significantly to mathematical reasoning and problem solving.
In this exercise,:
- \( \langle N, < \rangle \) denotes the natural numbers with their conventional order, starting from 0.
- \( \langle N - \{0\}, < \rangle \) represents positive natural numbers starting from 1, keeping the same order.
Understanding the order within these structures reveals deeper insights into how systems evolve, interact, and can be manipulated. Whether dealing with number systems, geometries, or other forms of data, ordered structures contribute significantly to mathematical reasoning and problem solving.