Chapter 3: Problem 3
Let \(\mathfrak{A} \subseteq \mathfrak{B} . \varphi\) is called universal (existential) if \(\varphi\) is prenex with only universal (existential) quantifiers. (i) Show that for universal sentences \(\varphi \mathfrak{B} \models \varphi \Rightarrow \mathfrak{A} \models \varphi\). (ii) Show that for existential sentences \(\varphi \mathfrak{A} \models \varphi \Rightarrow \mathfrak{B} \models \varphi\). (Application: a substructure of a group is a group. This is one reason to use the similarity type \(\langle-; 2,1 ; 1\rangle\) for groups, instead of \(\langle-; 2 ; 0\rangle\), or \(\langle-; 2 ; 1\rangle\), as some authors do).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.