Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Show (a) \(\varphi \models \varphi\); (b) \(\varphi \models \psi\) and \(\psi \models \sigma \Rightarrow \varphi \models \sigma\); (c) \(\models \varphi \rightarrow \psi \Rightarrow \varphi \models \psi\).

Short Answer

Expert verified
(a) Reflexive; (b) Transitive; (c) Follows from Deduction Theorem.

Step by step solution

01

Understand Reflexivity

We need to show \( \varphi \models \varphi \). This is known as the reflexivity of entailment. An interpretation that makes \( \varphi \) true will necessarily make \( \varphi \) true, because it is the same formula.
02

Apply Reflexivity

For any interpretation \( I \), if \( I \models \varphi \), then it is trivially true that \( I \models \varphi \). Therefore, \( \varphi \models \varphi \) holds for any formula \( \varphi \).
03

Understand Transitivity

We need to show \( \varphi \models \psi \) and \( \psi \models \sigma \Rightarrow \varphi \models \sigma \). This is known as the transitivity of entailment. If \( \varphi \) entails \( \psi \) and \( \psi \) entails \( \sigma \), then \( \varphi \) must also entail \( \sigma \).
04

Apply Transitivity

Assume \( \varphi \models \psi \) and \( \psi \models \sigma \) hold. For any interpretation \( I \) such that \( I \models \varphi \), it follows that \( I \models \psi \). Likewise, since \( I \models \psi \), it follows that \( I \models \sigma \). Thus, \( \varphi \models \sigma \).
05

Understand Deduction Theorem

We need to show \( \models \varphi \rightarrow \psi \Rightarrow \varphi \models \psi \). This leverages the deductive relationship between propositions, meaning that if \( \varphi \rightarrow \psi \) is a tautology, then \( \varphi \) entails \( \psi \).
06

Apply Deduction Theorem

Consider \( \models \varphi \rightarrow \psi \). For any interpretation \( I \) such that \( I \models \varphi \), the implication \( \varphi \rightarrow \psi \) must also hold since \( \varphi \rightarrow \psi \) is a tautology. Hence, \( I \models \psi \). Therefore, \( \varphi \models \psi \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reflexivity in Logic
Reflexivity in logic is a foundational concept that states a logical formula is always entailed by itself. This idea is often expressed as \( \varphi \models \varphi \). When we talk about entailment, we mean that if something holds true in one scenario, it should also hold true in related scenarios. In the case of reflexivity, it's about the simplest scenario: the same proposition.

Let's break it down: If you have a formula \( \varphi \), and an interpretation (or a situation) where \( \varphi \) is true, then obviously, in that same interpretation, \( \varphi \) will still be true. This may seem redundant, but it underlines the consistency of logic. No new conditions need to apply in this interpretation for it to be true again.
  • It's like saying, "If it's raining, then it's raining." This is inherently true without needing further demonstration.
  • It establishes a basis for more complex logic principles by showing logical reliability.
Reflexivity is pivotal in formal logic systems, highlighting the self-evident nature of truths within a single proposition.
Transitivity in Logic
Transitivity in logic helps us connect different propositions logically. It expresses the idea that if one thing leads to a second, and that second thing leads to a third, then the first thing should naturally lead to the third. Formally, we write this as: if \( \varphi \models \psi \) and \( \psi \models \sigma \), then \( \varphi \models \sigma \).

This principle is very important in proving that logical arguments hold true across different steps.
  • It allows us to extend the reasoning process by chaining entailments.
  • By understanding that each step pushes the implication further, it simplifies complex reasoning by breaking it into manageable parts.
For instance, imagine you have three facts: A implies B, and B implies C. With transitivity, you can immediately conclude that A implies C.

Thus, transitivity is a powerful tool in logic, assisting in the process of deduction, ensuring that conclusions remain consistent and valid over a chain of statements.
Deduction Theorem
The Deduction Theorem is a significant principle in mathematical logic that relates implications to entailment. In essence, it shows how we can derive one proposition from another by using logical implications. Specifically, it states if \( \models \varphi \rightarrow \psi \) is valid, then \( \varphi \models \psi \).

What this means is when the implication \( \varphi \rightarrow \psi \) is a tautology – universally true – we can deduce that wherever \( \varphi \) holds true, \( \psi \) must also be true.
  • This principle is useful for deriving conclusions from assumptions.
  • It bridges the gap between proof and implication, illustrating how a provable implication can be translated into a logical entailment.
For example, if we can prove that "If George is in the kitchen, then the light is on" is always true, then whenever George is indeed in the kitchen, we can confidently say that the light must be on.

This theorem empowers the proof processes in mathematics and computer science by linking assumptions and derived conclusions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The size, \(s(\mathcal{D})\), of a derivation is the number of proposition occurrences in \(\mathcal{D}\). Give an inductive definition of \(s(\mathcal{D})\). Show that one can prove properties of derivations by it induction on the size.

Show that the relation "is a subformula of" is transitive.

Check by the truth table method which of the following propositions are tautologies (a) \((\neg \varphi \vee \psi) \leftrightarrow(\psi \rightarrow \varphi)\) (b) \(\varphi \rightarrow((\psi \rightarrow \sigma) \rightarrow((\varphi \rightarrow \psi) \rightarrow(\varphi \rightarrow \sigma)))\) (c) \((\varphi \rightarrow \neg \varphi) \leftrightarrow \neg \varphi\) (d) \(\neg(\varphi \rightarrow \neg \varphi)\) (e) \((\varphi \rightarrow(\psi \rightarrow \sigma)) \leftrightarrow((\varphi \wedge \psi) \rightarrow \sigma)\) (f) \(\varphi \vee \neg \varphi\) (principle of the excluded third) (g) \(\perp \leftrightarrow(\varphi \wedge \neg \varphi)\) (h) \(\perp \rightarrow \varphi\) (ex falso sequitur quodlibet)

Show that \(\\{\neg\\}\) is not a functionally complete set of connectives. Idem for \(\\{\rightarrow, \vee\\}\) (hint: show that each formula \(\varphi\) with only \(\rightarrow\) and \(\vee\) there is a valuation \(v\) such that \(\llbracket \varphi \rrbracket=1\) ).

Let the ternary connective \(\$$ be defined by \)\llbracket \$\left(\varphi_{1}, \varphi_{2}, \varphi_{3}\right) \rrbracket=1 \Leftrightarrow\( \)\left.\llbracket \varphi_{1} \rrbracket+\llbracket \varphi_{2}\right]+\left[\varphi_{3}\right] \geq 2\( (the majority connective). Express \)\$$ in terms of \(\vee\) and \(\neg\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free