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(a) Consider a linear transformationT from 5to 3. What are the possible values of dim(kerT)? Explain.

(b) Consider a linear transformationT from 4to 7. What are the possible values of dim(imT)? Explain.

Short Answer

Expert verified

Thus,

(a) the possible values of dimKer(T)are 5,4,3,2.

(b) the possible values ofdimIm(T) are 0,1,2,3,4.

Step by step solution

01

(a) Possible values of dim(kerT).

The rank of a3×5matrix is bounded by 3, so it is equal to 0,1,2,3. Therefore,dimKer(T)=5rk(T) is equal to 5,4,3,2.

Hence, the possible values of dimKer(T)are 5,4,3,2.

02

(b) Possible values ofdim(imT). 

The rank of a matrix is bounded by 4, so it is equal to 0,1,2,3,4. Therefore, dimIm(T)=rk(T) is equal to 0,1,2,3,4.

Hence, the possible values ofdimIm(T) are 0,1,2,3,4.

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