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The vectors of the form ab0a(where a and b are arbitrary real numbers) forms a subspace ofR4.

Short Answer

Expert verified

The above statement is true.

If W be the collection of the vectors of the formab0a, then W forms a subspace ofR4.

Step by step solution

01

Two Step Subspace Test

  • Let V be a vector space over the field K. Let W be a subset of V, then W be a subspace of V if and only if -
  1. 0W
  2. u,vWu+vW
  3. uW,aFauW
02

To check whether the given form vectors form a subspace of R4.

Let W be the collection of the vectors of the form ab0ainR4.

Letu,vW then we have

u=ab0a,v=cd0c

Clearly, we see that W is non empty as

0000W

Now,

u+V=ab0a+cd0c=a+cb+d0a+cW

u+vW

And for γF,anduW, we have

γu=γab0aγaγb0γaW

03

Final Answer

If, W be the collection of the vectors of the form ab0ainR4 androle="math" localid="1664262248842" u,vW then we have

  1. 0W
  2. u,vWu+vW
  3. uW,aFauW

Since, subset W ofR4 satisfies all the above three conditions, thus W is a subspace of data-custom-editor="chemistry" R4.

Thus, the vectors of the form forms ab0athe subspace ofR4 .

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