Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercise 40 through 46, consider vectors v1,v2,v3in role="math" localid="1659606624550" R4; we are told that vi,vjis the entry data-custom-editor="chemistry" aijof matrix A.

A=[35115920112049]

Find ||v1+v2||

Short Answer

Expert verified

The value of||v1+v2|| is 4.69.

Step by step solution

01

Step by step answerStep 1: Given

The given matrix is A=[35115920112049].

02

Determine the value of ||v→1+v→2||

To find the value of ||v1+v2||. Let us write the matrix in the vi.vjnotation.

Consider the terms below:

A=[35115920112049]=v1.v1v1.v2v1.v3v2.v1v2.v2v2.v3v3.v1v3.v2v3.v3=||v1||2v1.v2v1.v3v2.v1||v2||2v2.v3v3.v1v3.v2||v3||2

Now, compute the above terms in the form of ||v1+v2||:

||v1+v2||2=(v1+v2)·(v1+v2)=v1.v1+v1.v2+v2.v1+v2.v2=3+5+5+9=22||v1+v2||=224.69

Thus,

||v1+v2||4.69

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free