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Suppose Aand B are orthogonally diagonalizable and \(AB = BA\). Explain why \(AB\) is also orthogonally diagonalizable.

Short Answer

Expert verified

The matrix AB is orthogonally diagonizable.

Step by step solution

01

Check matrices A and B

Since matrices A and B are orthogonally diagonalizable, sothe matrix is also symmetric, thus \({A^T} = A\), and \({B^T} = B\) (Theorem 2).

02

Check whether AB is orthogonally diagonalizable

Use the transpose property for \(AB\).

\(\begin{aligned}{}{\left( {AB} \right)^T} &= {B^T}{A^T}\\ &= BA\\ &= AB\end{aligned}\)

Matrix AB is also symmetric.

Thus, the matrix AB is orthogonally diagonizable.

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