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In Exercises 19 and 20, all vectors are in \({\mathbb{R}^n}\). Mark each statement True or False. Justify each answer.

  1. \(v \cdot {\rm{v}} = {\left\| {\rm{v}} \right\|^2}\).
  2. For any scalar \(c\),\({\rm{u}} \cdot \left( {c{\rm{v}}} \right) = c\left( {{\rm{u}} \cdot {\rm{v}}} \right)\).
  3. If the distance from \({\rm{u}}\) to \({\rm{v}}\) equals the distance from \({\rm{u}}\) to \( - {\rm{v}}\), then \({\rm{u}}\) and \({\rm{v}}\) are orthogonal.
  4. For a square matrix \(A\), vectors in \({\rm{Col }}A\) are orthogonal to vectors in Nul \(A\).
  5. If vectors \({{\rm{v}}_1}..........,{{\rm{v}}_p}\) span a subspace \(W\) and if \({\rm{x}}\) is orthogonal to each \({{\rm{v}}_j}\) for \(j = 1,..........,p\), then \({\rm{x}}\) is in \({W^ \bot }\)?.

Short Answer

Expert verified
  1. True, by using the definition of the length of the vector.
  2. True, by using Theorem 1(c).
  3. True, by using the definition of orthogonal vectors.
  4. False, as the case fails when the square matrix is not symmetric.
  5. True, by using the definition for the spans of any vector.

Step by step solution

01

Definition of Orthogonal Set

The two vectors \({\rm{u and v}}\) are Orthogonal if:

\(\begin{aligned}{l}{\left\| {{\bf{u}} + {\bf{v}}} \right\|^2} = {\left\| {\bf{u}} \right\|^2} + {\left\| {\bf{v}} \right\|^2}\\{\rm{and}}\\{\bf{u}} \cdot {\bf{v}} = 0\end{aligned}\).

02

 Verification of statement (a)

The definition for the length of any vector states that:

\({\left\| {\bf{v}} \right\|^2} = {\bf{v}} \cdot {\bf{v}}\)

Hence, the given statement is true.

03

 Verification of statement (b)

The Theorem 1(c)resembles that:

\(\left( {c{\bf{u}}} \right) \cdot {\bf{v}} = c\left( {{\bf{u}} \cdot {\bf{v}}} \right) = {\bf{u}} \cdot \left( {c{\bf{v}}} \right)\)

Hence, the given statement is true.

04

 Verification of statement (c)

The definition of the Orthogonal Vectorsstates that:

\(\begin{aligned}{l}{\left\| {{\bf{u}} + {\bf{v}}} \right\|^2} = {\left\| {\bf{u}} \right\|^2} + {\left\| {\bf{v}} \right\|^2}\\{\rm{and}}\\{\bf{u}} \cdot {\bf{v}} = 0\end{aligned}\)

Hence, the given statement is true.

05

 Verification of statement (d)

The given statement is only valid for the particular type of square matrices. Just in case if there is a matrix of type:

\(A = \left( {\begin{aligned}{*{20}{c}}1&1\\0&0\end{aligned}} \right)\)

The given statement would not be true.

Hence, the given statement is False.

06

 Verification of statement (e)

The definition for the spans of any vector states that for the given condition in question, the span:

\({W^ \bot } \subseteq {\mathbb{R}^n}\)

Hence, the given statement is true.

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Most popular questions from this chapter

In Exercises 11 and 12, find the closest point to\[{\bf{y}}\]in the subspace\[W\]spanned by\[{{\bf{v}}_1}\], and\[{{\bf{v}}_2}\].

11.\[y = \left[ {\begin{aligned}3\\1\\5\\1\end{aligned}} \right]\],\[{{\bf{v}}_1} = \left[ {\begin{aligned}3\\1\\{ - 1}\\1\end{aligned}} \right]\],\[{{\bf{v}}_2} = \left[ {\begin{aligned}1\\{ - 1}\\1\\{ - 1}\end{aligned}} \right]\]

Let \(X\) be the design matrix used to find the least square line of fit data \(\left( {{x_1},{y_1}} \right), \ldots ,\left( {{x_n},{y_n}} \right)\). Use a theorem in Section 6.5 to show that the normal equations have a unique solution if and only if the data include at least two data points with different \(x\)-coordinates.

In Exercises 1-6, the given set is a basis for a subspace W. Use the Gram-Schmidt process to produce an orthogonal basis for W.

  1. \(\left( {\begin{aligned}{{}{}}3\\0\\{ - 1}\end{aligned}} \right),\left( {\begin{aligned}{{}{}}8\\5\\{ - 6}\end{aligned}} \right)\)

Given data for a least-squares problem, \(\left( {{x_1},{y_1}} \right), \ldots ,\left( {{x_n},{y_n}} \right)\), the following abbreviations are helpful:

\(\begin{aligned}{l}\sum x = \sum\nolimits_{i = 1}^n {{x_i}} ,{\rm{ }}\sum {{x^2}} = \sum\nolimits_{i = 1}^n {x_i^2} ,\\\sum y = \sum\nolimits_{i = 1}^n {{y_i}} ,{\rm{ }}\sum {xy} = \sum\nolimits_{i = 1}^n {{x_i}{y_i}} \end{aligned}\)

The normal equations for a least-squares line \(y = {\hat \beta _0} + {\hat \beta _1}x\) may be written in the form

\(\begin{aligned}{c}{{\hat \beta }_0} + {{\hat \beta }_1}\sum x = \sum y \\{{\hat \beta }_0}\sum x + {{\hat \beta }_1}\sum {{x^2}} = \sum {xy} {\rm{ (7)}}\end{aligned}\)

Derive the normal equations (7) from the matrix form given in this section.

Find an orthonormal basis of the subspace spanned by the vectors in Exercise 3.

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