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In Exercises 1 and 2, compute each matrix sum or product if it is defined. If an expression is undefined, explain why. Let

\(A = \left( {\begin{aligned}{*{20}{c}}2&0&{ - 1}\\4&{ - 5}&2\end{aligned}} \right)\), \(B = \left( {\begin{aligned}{*{20}{c}}7&{ - 5}&1\\1&{ - 4}&{ - 3}\end{aligned}} \right)\), \(C = \left( {\begin{aligned}{*{20}{c}}1&2\\{ - 2}&1\end{aligned}} \right)\), \(D = \left( {\begin{aligned}{*{20}{c}}3&5\\{ - 1}&4\end{aligned}} \right)\) and \(E = \left( {\begin{aligned}{*{20}{c}}{ - 5}\\3\end{aligned}} \right)\)

\(A + 2B\), \(3C - E\), \(CB\), \(EB\).

Short Answer

Expert verified

\(A + 2B = \left( {\begin{aligned}{*{20}{c}}{16}&{ - 10}&1\\6&{ - 13}&{ - 4}\end{aligned}} \right)\),

\(3C - E\)is not defined;

\(CB = \left( {\begin{aligned}{*{20}{c}}9&{ - 13}&{ - 5}\\{ - 13}&6&{ - 5}\end{aligned}} \right)\)and

\(EB\) is not defined.

Step by step solution

01

Find the matrix \(A + 2B\)

The value of \(A + 2B\) can be calculated as follows:

\(\begin{aligned}{c}A + 2B = \left( {\begin{aligned}{*{20}{c}}2&0&{ - 1}\\4&{ - 5}&2\end{aligned}} \right) + 2\left( {\begin{aligned}{*{20}{c}}7&{ - 5}&1\\1&{ - 4}&{ - 3}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}2&0&{ - 1}\\4&{ - 5}&2\end{aligned}} \right) + \left( {\begin{aligned}{*{20}{c}}{14}&{ - 10}&2\\2&{ - 8}&{ - 6}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}{16}&{ - 10}&1\\6&{ - 13}&{ - 4}\end{aligned}} \right)\end{aligned}\)

02

Find the matrix \({\bf{3}}C - E\)

The value of \(3C - E\) is not defined as \(C\) has 2 columns, whereas \(E\) has 1 column.

03

Find the matrix \(CB\)

The value \(CB\) can be calculated as follows:

\(\begin{aligned}{c}CB = \left( {\begin{aligned}{*{20}{c}}1&2\\{ - 2}&1\end{aligned}} \right) \times \left( {\begin{aligned}{*{20}{c}}7&{ - 5}&1\\1&{ - 4}&{ - 3}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}{1 \times 7 + 2 \times 1}&{1 \times \left( { - 5} \right) + 2 \times \left( { - 4} \right)}&{1 \times 1 + 2 \times \left( { - 3} \right)}\\{\left( { - 2} \right) \times 7 + 1 \times 1}&{\left( { - 2} \right) \times \left( { - 5} \right) + 1 \times \left( { - 4} \right)}&{\left( { - 2} \right) \times 1 + 1 \times \left( { - 3} \right)}\end{aligned}} \right)\\ = \left( {\begin{aligned}{*{20}{c}}9&{ - 13}&{ - 5}\\{ - 13}&6&{ - 5}\end{aligned}} \right)\end{aligned}\)

04

Find the matrix \(EB\)

The product \(EB\) is not defined as the number of columns in \(E\) does not match the number of rows of \(B\).

So, \(A + 2B = \left( {\begin{aligned}{*{20}{c}}{16}&{ - 10}&1\\6&{ - 13}&{ - 4}\end{aligned}} \right)\) and \(3C - E\) are not defined; \(CB = \left( {\begin{aligned}{*{20}{c}}9&{ - 13}&{ - 5}\\{ - 13}&6&{ - 5}\end{aligned}} \right)\) and \(EB\) are not defined.

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Most popular questions from this chapter

Suppose the first two columns, \({{\bf{b}}_1}\) and \({{\bf{b}}_2}\), of Bare equal. What can you say about the columns of AB(if ABis defined)? Why?

Let \(T:{\mathbb{R}^n} \to {\mathbb{R}^n}\) be an invertible linear transformation. Explain why T is both one-to-one and onto \({\mathbb{R}^n}\). Use equations (1) and (2). Then give a second explanation using one or more theorems.

Suppose A, B, and Care \(n \times n\) matrices with A, X, and \(A - AX\) invertible, and suppose

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A useful way to test new ideas in matrix algebra, or to make conjectures, is to make calculations with matrices selected at random. Checking a property for a few matrices does not prove that the property holds in general, but it makes the property more believable. Also, if the property is actually false, you may discover this when you make a few calculations.

38. Use at least three pairs of random \(4 \times 4\) matrices Aand Bto test the equalities \({\left( {A + B} \right)^T} = {A^T} + {B^T}\) and \({\left( {AB} \right)^T} = {A^T}{B^T}\). (See Exercise 37.) Report your conclusions. (Note:Most matrix programs use \(A'\) for \({A^{\bf{T}}}\).

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