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The figure shows vectors \(u\), \(v\) and \(w\) along with the images \(T\left( u \right)\) and \(T\left( v \right)\) under the action of a linear transformation \(T:{\mathbb{R}^2} \to {\mathbb{R}^2}\). Copy this figure carefully, and draw the image \(T\left( w \right)\) as accurately as possible. [Hint: First write \(w\) as a linear combination of \(u\) and \(v\).]

Short Answer

Expert verified

In the first figure, draw lines through the head of \(w\), where one is parallel to \(v\) and the other parallel to \(u\).

From the figure, it can be estimated that

\(w = u + 2v\)

Step by step solution

01

Use the graph find the relation between \(u\), \(v\), and \(w\)

In the first figure, draw lines through the head of \(w\), where one is parallel to \(v\) and the other parallel to \(u\).

From the figure, it can be estimated that

\(w = u + 2v\)

02

Find the linear transformation

As \(T\) is linear, the transformation is:

\(\begin{aligned}T\left( w \right) &= T\left( u \right) + T\left( {2v} \right)\\ &= T\left( u \right) + 2T\left( v \right)\end{aligned}\)

03

Drawing the image for \(T\left( w \right)\)

Draw \(2T\left( v \right)\) in the right figure and a line parallel to \(T\left( u \right)\) through the head of \(2T\left( v \right)\) and another line parallel to \(2T\left( v \right)\) through the head of \(T\left( u \right)\).

So, the diagonal of the parallelogram in the above figure is \(T\left( w \right)\).

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Most popular questions from this chapter

Solve the linear system of equations. You may use technology.

|3x+5y+3z=257X+9y+19z=654X+5y+11z=5|

Explain why a set \(\left\{ {{{\mathop{\rm v}\nolimits} _1},{{\mathop{\rm v}\nolimits} _2},{{\mathop{\rm v}\nolimits} _3},{{\mathop{\rm v}\nolimits} _4}} \right\}\) in \({\mathbb{R}^5}\) must be linearly independent when \(\left\{ {{{\mathop{\rm v}\nolimits} _1},{{\mathop{\rm v}\nolimits} _2},{{\mathop{\rm v}\nolimits} _3}} \right\}\) is linearly independent and \({{\mathop{\rm v}\nolimits} _4}\) is not in Span \(\left\{ {{{\mathop{\rm v}\nolimits} _1},{{\mathop{\rm v}\nolimits} _2},{{\mathop{\rm v}\nolimits} _3}} \right\}\).

Find the general solutions of the systems whose augmented matrices are given as

14. \(\left[ {\begin{array}{*{20}{c}}1&2&{ - 5}&{ - 6}&0&{ - 5}\\0&1&{ - 6}&{ - 3}&0&2\\0&0&0&0&1&0\\0&0&0&0&0&0\end{array}} \right]\).

Let \({{\mathop{\rm v}\nolimits} _1} = \left[ {\begin{array}{*{20}{c}}1\\0\\{ - 2}\end{array}} \right],{v_2} = \left[ {\begin{array}{*{20}{c}}{ - 3}\\1\\8\end{array}} \right],\) and \({\rm{y = }}\left[ {\begin{array}{*{20}{c}}h\\{ - 5}\\{ - 3}\end{array}} \right]\). For what values(s) of \(h\) is \(y\) in the plane generated by \({{\mathop{\rm v}\nolimits} _1}\) and \({{\mathop{\rm v}\nolimits} _2}\)

Consider a dynamical system xโ†’(t+1)=Axโ†’(t)with two components. The accompanying sketch shows the initial state vector xโ†’0and two eigenvectors ฯ…1โ†’โ€Šโ€Šandโ€Šโ€Šฯ…2โ†’of A (with eigen values ฮป1โ†’andฮป2โ†’ respectively). For the given values of ฮป1โ†’andฮป2โ†’, draw a rough trajectory. Consider the future and the past of the system.

ฮป1โ†’=1.2,ฮป2โ†’=1.1

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