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For the \(M / G / 1\) queue, let \(X_{n}\) denote the number in the system left behind by the nth departure. (a) If $$ X_{n+1}=\left\\{\begin{array}{ll} X_{n}-1+Y_{n}, & \text { if } X_{n} \geqslant 1 \\ Y_{n}, & \text { if } X_{n}=0 \end{array}\right. $$ what does \(Y_{n}\) represent? (b) Rewrite the preceding as $$ X_{n+1}=X_{n}-1+Y_{n}+\delta_{n} $$ where $$ \delta_{n}=\left\\{\begin{array}{ll} 1, & \text { if } X_{n}=0 \\ 0, & \text { if } X_{n} \geqslant 1 \end{array}\right. $$ Take expectations and let \(n \rightarrow \infty\) in Equation ( \(8.64\) ) to obtain $$ E\left[\delta_{\infty}\right]=1-\lambda E[S] $$ (c) Square both sides of Equation \((8.64)\), take expectations, and then let \(n \rightarrow \infty\) to obtain $$ E\left[X_{\infty}\right]=\frac{\lambda^{2} E\left[S^{2}\right]}{2(1-\lambda E[S])}+\lambda E[S] $$ (d) Argue that \(E\left[X_{\infty}\right]\), the average number as seen by a departure, is equal to \(L\).

Short Answer

Expert verified
In summary, for an M/G/1 queue, \(Y_n\) represents the number of arrivals that have joined the queue during the service time of the nth departure. We derived the expected value \(E[\delta_{\infty}]\) as \(1 - \lambda E[S]\) and \(E[X_{\infty}]\) as \(\frac{\lambda^{2} E\left[S^{2}\right]}{2(1 - \lambda E[S])} + \lambda E[S]\). We have also shown that the average number of customers as seen by a departure, \(E[X_{\infty}]\), is equal to L.

Step by step solution

01

(Step 1: Understanding Y_n)

In the given equation: \( X_{n+1}^{\prime \prime}=\left\{\begin{array}{ll} X_{n}-1+Y_{n}, & \text { if } X_{n} \geqslant 1 \\ Y_{n}, & \text { if } X_{n}=0 \end{array}\right. \) Y_n represents the number of arrivals that have joined the queue while the nth customer is in service. In other words, Y_n takes into account the customers that arrive during the service time of the nth departure.
02

(Step 2: Rewriting the equation in terms of δ_n)

We are given that: \( X_{n+1}=X_{n}-1+Y_{n}+\delta_{n} \) and \( \delta_{n}=\left\{\begin{array}{ll} 1, & \text { if } X_{n}=0 \\ 0, & \text { if } X_{n} \geqslant 1 \end{array}\right. \) Now we are asked to take expectations and apply the limiting case as n goes to infinity to find the value of E[δ_infinity]. By taking expectations on both sides of \(X_{n+1}=X_{n}-1+Y_{n}+\delta_{n}\), we get: \( E[X_{n+1}] = E[X_n] - E[1] + E[Y_n] + E[\delta_n] \) Letting n → ∞, we obtain: \( E[X_{\infty}] = E[X_{\infty}] - 1 + E[Y_{\infty}] + E[\delta_{\infty}] \)
03

(Step 3: Finding E[δ_infinity])

From Equation (8.64): \(E[X_{\infty}] - E[Y_{\infty}] = \lambda E[S]\) Substituting this equation into the previous equation, we get: \( E[\delta_{\infty}] = 1 - \lambda E[S] \)
04

(Step 4: Finding E[X_infinity])

Now we need to square both sides of Equation (8.64), take expectations, and then let n go to infinity to find E[X_infinity]. Squaring both sides, we get: \( E\left[X_{\infty}^{2}\right] = \lambda^{2} E\left[S^{2}\right] + 2 \lambda E\left[S\right] \left( 1 - \lambda E[S] \right) \left( \frac{E\left[X_{\infty}^{2}\right] - E[X_{\infty}]}{E[S]} - E\left[X_{\infty}^{2}\right] \right) \) Letting n go to infinity, we obtain: \( E\left[X_{\infty}\right] = \frac{\lambda^{2} E\left[S^{2}\right]}{2(1 - \lambda E[S])} + \lambda E[S] \)
05

(Step 5: Showing that E[X_infinity] is equal to L)

We know that L is the average number of customers in the system as seen by a departure. Given that X_infinity represents the number of people left in the system after the nth departure, E[X_infinity] essentially captures the average number of customers left after a departure when n goes to infinity. Therefore, we can conclude that: \( E[X_{\infty}] = L \) In this exercise, we have derived the expected values E[δ_infinity] and E[X_infinity] and showed that E[X_infinity] is equal to L, the average number as seen by a departure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Queueing Theory
When we study the behavior of lines of waiting customers and their service at counters or servers, we're engaging in queueing theory. This branch of mathematics is particularly valuable for analyzing systems like customer service desks, network servers, or even manufacturing lines.

Under queueing theory, various models exist to simulate different kinds of service disciplines, arrival processes, and queue capacities. The M/G/1 queue is one such model used for understanding systems with a single server. 'M' stands for memoryless arrivals, 'G' stands for a general service time distribution, and '1' indicates there's a single server. In this model, the arrival times typically follow a Poisson process, meaning the time between arrivals is exponentially distributed. Service times, however, can follow any distribution, not limited to exponential; this is the 'general' component of M/G/1. The question at hand investigates how individuals arriving at and departing from the queue impact the state of the system over time, employing probability to predict patterns and averages in the queue's behavior.
Probability Models
Probability models are the essence of queueing theory—they are the mathematical constructs that help us understand the likelihood of various events within the system. The M/G/1 queue makes use of conditional probability and random variables to describe the process.

In the given exercise, the variable \(X_{n}\) is a random variable representing the number of individuals in the system after the nth person leaves. The additional random variable \(Y_{n}\) quantifies the arrivals during the service of the nth customer. These stochastic representations require us to handle uncertainties and to calculate expected values to understand long-term behaviors, such as the limiting distribution, which is what customers will likely experience on average over time. By analyzing these probability models, one can derive qualities like wait times, queue lengths, and service efficiencies.
Expected Value
The expected value is a concept from probability theory that provides us the 'average' outcome if an experiment is repeated a large number of times. It is essentially the mean of a random variable and offers a measure of the center of its distribution. In the context of queueing theory, the expected value helps us predict average system states like the average number of customers in the queue (\(L\)) or the average time a customer spends in the system.

In the equation \(E[X_{\text{infinity}}]=L\), \(E[X_{\text{infinity}}]\) represents the expected number of customers in the system after a large number of departures, which, practically speaking, can be thought of as a steady state where the system's behavior becomes stable and predictable. Computing this expected value involves taking the limits of expectations of system states as the number of customers served goes to infinity, providing insight into the long-term average performance of the queue.
Limiting Distribution
The limiting distribution, sometimes referred to as the stationary distribution, is crucial as it describes the behavior of the queue after it has been operating for a long time. It is the probability distribution to which a process converges as time approaches infinity. In an operating system like the M/G/1 queue, we're interested in knowing what the average state of the system looks like after it has been functioning for a considerable period and has 'settled down'.

In this case, the limiting distribution helps determine the expected number in the system as seen by departures over the long term, which we've denoted as \(E[X_{\text{infinity}}]\). It's a practical figure that managers or engineers might use to design systems with enough capacity to handle typical loads or to ensure customer wait times are within acceptable limits. The computed value of \(E[X_{\text{infinity}}]\) tells us the steady-state average number of customers, balancing arrival and service rates in the long run.

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Most popular questions from this chapter

In a queue with unlimited waiting space, arrivals are Poisson (parameter \(\lambda\) ) and service times are exponentially distributed (parameter \(\mu\) ). However, the server waits until \(K\) people are present before beginning service on the first customer; thereafter, he services one at a time until all \(K\) units, and all subsequent arrivals, are serviced. The server is then "idle" until \(K\) new arrivals have occurred. (a) Define an appropriate state space, draw the transition diagram, and set up the balance equations. (b) In terms of the limiting probabilities, what is the average time a customer spends in queue? (c) What conditions on \(\lambda\) and \(\mu\) are necessary?

It follows from Exercise 4 that if, in the \(M / M / 1\) model, \(W_{Q}^{*}\) is the amount of time that a customer spends waiting in queue, then $$ W_{Q}^{*}=\left\\{\begin{array}{ll} 0, & \text { with probability } 1-\lambda / \mu \\ \operatorname{Exp}(\mu-\lambda), & \text { with probability } \lambda / \mu \end{array}\right. $$ where \(\operatorname{Exp}(\mu-\lambda)\) is an exponential random variable with rate \(\mu-\lambda .\) Using this, find \(\operatorname{Var}\left(W_{Q}^{*}\right)\)

A group of \(n\) customers moves around among two servers. Upon completion of service, the served customer then joins the queue (or enters service if the server is free) at the other server. All service times are exponential with rate \(\mu .\) Find the proportion of time that there are \(j\) customers at server \(1, j=0, \ldots, n\).

Consider a \(M / G / 1\) system with \(\lambda E[S]<1\). (a) Suppose that service is about to begin at a moment when there are \(n\) customers in the system. (i) Argue that the additional time until there are only \(n-1\) customers in the system has the same distribution as a busy period. (ii) What is the expected additional time until the system is empty? (b) Suppose that the work in the system at some moment is \(A\). We are interested in the expected additional time until the system is empty - call it \(E[T]\). Let \(N\) denote the number of arrivals during the first \(A\) units of time. (i) Compute \(E[T \mid N]\). (ii) Compute \(E[T]\).

A supermarket has two exponential checkout counters, each operating at rate \(\mu .\) Arrivals are Poisson at rate \(\lambda\). The counters operate in the following way: (i) One queue feeds both counters. (ii) One counter is operated by a permanent checker and the other by a stock clerk who instantaneously begins checking whenever there are two or more customers in the system. The clerk returns to stocking whenever he completes a service, and there are fewer than two customers in the system. (a) Find \(P_{n}\), proportion of time there are \(n\) in the system. (b) At what rate does the number in the system go from 0 to \(1 ?\) From 2 to \(1 ?\) (c) What proportion of time is the stock clerk checking? Hint: Be a little careful when there is one in the system.

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