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Potential customers arrive to a single-server hair salon according to a Poisson process with rate \(\lambda .\) A potential customer who finds the server free enters the system; a potential customer who finds the server busy goes away. Each potential customer is type \(i\) with probability \(p_{i}\), where \(p_{1}+p_{2}+p_{3}=1\). Type 1 customers have their hair washed by the server; type 2 customers have their hair cut by the server; and type 3 customers have their hair first washed and then cut by the server. The time that it takes the server to wash hair is exponentially distributed with rate \(\mu_{1}\), and the time that it takes the server to cut hair is exponentially distributed with rate \(\mu_{2}\). (a) Explain how this system can be analyzed with four states. (b) Give the equations whose solution yields the proportion of time the system is in each state. In terms of the solution of the equations of (b), find (c) the proportion of time the server is cutting hair; (d) the average arrival rate of entering customers.

Short Answer

Expert verified
(a) The system can be analyzed with four states: - State 0: The system is empty (no customer is being served). - State 1: A customer of Type 1 is being served (hair is being washed). - State 2: A customer of Type 2 is being served (hair is being cut). - State 3: A customer of Type 3 is being served (hair is being washed and will be cut subsequently). (b) The balance equations for the four states are: - State 0: \(P_0 \lambda = (P_1 \mu_1) + (P_2 \mu_2) + (P_3 \mu_1)\). - State 1: \(P_0 (\lambda p_1) = P_1 \mu_1\). - State 2: \(P_0 (\lambda p_2) = P_2 \mu_2\). - State 3: \(P_0 (\lambda p_3) = P_3 \mu_1\). Additionally, \(P_0 + P_1 + P_2 + P_3 = 1\). (c) The proportion of time the server is cutting hair, \(P_{cut}\), is: \[P_{cut} = P_2 + \frac{P_3}{\mu_1 + \mu_2}.\] (d) The average arrival rate of entering customers, \(A_r\), is: \[A_r = \lambda P_0.\]

Step by step solution

01

a) Analyzing the System with Four States

To analyze the system with four states, we need to consider the possible occurrences in each state. We label the states as follows: - State 0: The system is empty (no customer is being served). - State 1: A customer of Type 1 is being served, i.e., their hair is being washed. - State 2: A customer of Type 2 is being served, i.e., their hair is being cut. - State 3: A customer of Type 3 is being served, i.e., their hair is being washed and will be cut subsequently. We describe a birth-death process with state transitions corresponding to arrivals and completions of service.
02

b) Finding the Equations for Proportion of Time

Now, let \(P_i\) denote the proportion of time the system is in state \(i\), where \(i=\{0,1,2,3\}\). We can write out the balance equations for the four states as follows. Keep in mind that the rate of arriving customers is \(\lambda\) and the service rates are \(\mu_1\) for hair washing and \(\mu_2\) for hair cutting: - State 0: \(P_0 \lambda = (P_1 \mu_1) + (P_2 \mu_2) + (P_3 \mu_1)\). - State 1: \(P_0 (\lambda p_1) = P_1 \mu_1\). - State 2: \(P_0 (\lambda p_2) = P_2 \mu_2\). - State 3: \(P_0 (\lambda p_3) = P_3 \mu_1\). Additionally, the sum of all probabilities must be equal to one, hence, \(P_0 + P_1 + P_2 + P_3 = 1\).
03

c) Proportion of Time Server is Cutting Hair

To find the proportion of time the server is cutting hair, we should sum up the proportion of time in State 2 (when a Type 2 customer is being served) and the proportion of time in State 3 (when a Type 3 customer is being served, but only after having their hair washed, i.e., the server is now cutting their hair). We can denote this by \(P_{cut}\): \[P_{cut} = P_2 + \frac{P_3}{\mu_1 + \mu_2}.\]
04

d) Average Arrival Rate of Entering Customers

To find the average arrival rate of entering customers, we will use the fact that the total rate of customers entering is \(\lambda\). However, only those customers who find the server free will enter the system. Thus, the average arrival rate of entering customers \(A_r\) can be calculated using the probability of finding the server idle (State 0): \[A_r = \lambda P_0.\]

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Most popular questions from this chapter

Suppose we want to find the covariance between the times spent in the system by the first two customers in an \(M / M / 1\) queueing system. To obtain this covariance, let \(S_{i}\) be the service time of customer \(i, i=1,2\), and let \(Y\) be the time between the two arrivals. (a) Argue that \(\left(S_{1}-Y\right)^{+}+S_{2}\) is the amount of time that customer 2 spends in the system, where \(x^{+}=\max (x, 0)\) (b) Find \(\operatorname{Cov}\left(S_{1},\left(S_{1}-Y\right)^{+}+S_{2}\right)\). Hint: Compute both \(E\left[(S-Y)^{+}\right]\) and \(E\left[S_{1}\left(S_{1}-Y\right)^{+}\right]\) by conditioning on whether \(S_{1}>Y\)

Consider a closed queueing network consisting of two customers moving among two servers, and suppose that after each service completion the customer is equally likely to go to either server-that is, \(P_{1,2}=P_{2,1}=\frac{1}{2}\). Let \(\mu_{i}\) denote the exponential service rate at server \(i, i=1,2\) (a) Determine the average number of customers at each server. (b) Determine the service completion rate for each server.

In a two-class priority queueing model suppose that a cost of \(C_{i}\) per unit time is incurred for each type \(i\) customer that waits in queue, \(i=1,2 .\) Show that type 1 customers should be given priority over type 2 (as opposed to the reverse) if $$ \frac{E\left[S_{1}\right]}{C_{1}}<\frac{E\left[S_{2}\right]}{C_{2}} $$

Consider a queueing system having two servers and no queue. There are two types of customers. Type 1 customers arrive according to a Poisson process having rate \(\lambda_{1}\), and will enter the system if either server is free. The service time of a type 1 customer is exponential with rate \(\mu_{1}\). Type 2 customers arrive according to a Poisson process having rate \(\lambda_{2}\). A type 2 customer requires the simultaneous use of both servers; hence, a type 2 arrival will only enter the system if both servers are free. The time that it takes (the two servers) to serve a type 2 customer is exponential with rate \(\mu_{2}\). Once a service is completed on a customer, that customer departs the system. (a) Define states to analyze the preceding model. (b) Give the balance equations. In terms of the solution of the balance equations, find (c) the average amount of time an entering customer spends in the system; (d) the fraction of served customers that are type \(1 .\)

Customers arrive at a single-server station in accordance with a Poisson process having rate \(\lambda .\) Each customer has a value. The successive values of customers are independent and come from a uniform distribution on \((0,1)\). The service time of a customer having value \(x\) is a random variable with mean \(3+4 x\) and variance \(5 .\) (a) What is the average time a customer spends in the system? (b) What is the average time a customer having value \(x\) spends in the system?

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