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There are two types of customers. Type 1 and 2 customers arrive in accordance with independent Poisson processes with respective rate \(\lambda_{1}\) and \(\lambda_{2}\). There are two servers. A type 1 arrival will enter service with server 1 if that server is free; if server 1 is busy and server 2 is free, then the type 1 arrival will enter service with server 2\. If both servers are busy, then the type 1 arrival will go away. A type 2 customer can only be served by server \(2 ;\) if server 2 is free when a type 2 customer arrives, then the customer enters service with that server. If server 2 is busy when a type 2 arrives, then that customer goes away. Once a customer is served by either server, he departs the system. Service times at server \(i\) are exponential with rate \(\mu_{i}\), \(i=1,2\) Suppose we want to find the average number of customers in the system. (a) Define states. (b) Give the balance equations. Do not attempt to solve them. In terms of the long-run probabilities, what is (c) the average number of customers in the system? (d) the average time a customer spends in the system?

Short Answer

Expert verified
To summarize, we defined the following states for our queuing system: state 0 when both servers are empty, state 1 when server 1 is busy and server 2 is empty, state 2 when server 1 is empty and server 2 is busy, and state 3 when both servers are busy. Using these states, we set up the balance equations and found the long-run probabilities. The average number of customers in the system is given by \(L = (0)P_0 + (1)P_1 + (1)P_2 + (2)P_3\), and the average time a customer spends in the system is given by \(W = \frac{L}{\lambda_1 + \lambda_2}\).

Step by step solution

01

1. Define States

To define the states, consider the following possible states of the system: - State 0: Both servers are empty. - State 1: Server 1 is busy, Server 2 is empty. - State 2: Server 1 is empty, Server 2 is busy. - State 3: Both servers are busy. The system is in state 0 if no customers are present; state 1 when a type 1 customer is being served by server 1; state 2 when a type 2 customer is served by server 2 or type 1 customer is served by server 2; and state 3 when server 1 serves a type 1 customer and server 2 serves a type 1 or type 2 customer.
02

2. Balance Equations

To derive the balance equations, we consider the inflow and outflow from the states. Let \(P_i\) be the long-run probability that the system is in state i. - For State 0: \[\lambda_1(P_1 - P_0) + \lambda_2(P_2 - P_0) = 0\] - For State 1: \[\lambda_1(P_0 - P_1) + (\lambda_1 + \lambda_2)(P_3 - P_1) + \mu_1(P_3 - P_1) = 0\] - For State 2: \[\lambda_1(P_3 - P_2) + \lambda_2(P_0 - P_2) + \mu_2(P_3 - P_2) = 0\] - For State 3: \[\lambda_1(P_1 - P_3) + \mu_1(P_1 - P_3) + \lambda_2(P_2 - P_3) + \mu_2(P_2-P_3) = 0\] Since these probabilities are long-run probabilities, we also have the normalization condition: \[P_0 + P_1 + P_2 + P_3 = 1\]
03

3. Average Number of Customers in System

The average number of customers in the system can be found by multiplying the number of customers in each state by the long-run probability of that state and totaling the result: \[L = (0)P_0 + (1)P_1 + (1)P_2 + (2)P_3\]
04

4. Average Time a Customer Spends in the System

We can use Little's theorem to find the average time a customer spends in the system, which states that \(L = \lambda W\), where \(L\) is the average number of customers in the system, \(\lambda\) is the total arrival rate, and \(W\) is the average time a customer spends in the system. In this case, the total arrival rate, \(\lambda = \lambda_1 + \lambda_2\). To find the average time a customer spends in the system, we rearrange the equation and solve for \(W\): \[W = \frac{L}{\lambda} = \frac{L}{\lambda_1 + \lambda_2}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balance Equations
In queueing theory, balance equations are pivotal in determining the long-term behavior of a system. They are used to model the flow of customers or packets in and out of various states within the system. Suppose we compare the rate at which customers leave each state with the rate at which they enter. The system is in equilibrium if these rates balance out, meaning the inflow and outflow are equal.

The exercise presents a system with two different types of customers and two servers, each with varied service rules. Formulating the balance equations involves a step by step assessment of the inflow and outflow probabilities for each state of the system. We use the rates at which the customers arrive and the servers process them, denoted by \(\lambda_i\) for arrival rates and \(\mu_i\) for service rates. The established balance equations do not require immediate solving but set the stage for understanding the system's dynamics and can later be used to calculate various performance metrics such as the average number of customers in the system and the average time they spend in the system.
Exponential Service Times

Understanding the Exponential Distribution

Exponential service times are a common assumption in the study of queueing systems, which implies the memoryless property – the probability of a service completion in the next instant is independent of how long the service has already been in process.

This characteristic is especially relevant in the given problem where each server processes customers one at a time and the service time is exponentially distributed with rates \(\mu_1\) and \(\mu_2\). This assumption not only simplifies the analysis by using these rates directly in the balance equations but also allows the application of Markovian properties for solving the queueing system.
Queueing Theory
Queueing theory is a mathematical study of waiting lines, or queues. At its core, it employs mathematical models to analyze various aspects of queues such as waiting times, queue lengths, and the efficiency of the queueing process.

The given exercise exemplifies a basic queue model where customers arrive according to a Poisson process. This is defined by random events occurring independently and at a constant average rate, which are common criteria in many real-world queueing scenarios. Queueing theory often leverages these stochastic processes to predict system behavior over time and is an essential tool in designing and managing systems where resources are shared, such as in customer service centers, computer networks, and manufacturing.
Little's Theorem
Little's theorem is a fundamental theorem in queueing theory that provides a critical link between the average number of customers in a system (L), the average arrival rate of customers to the system (\(\lambda\)), and the average time a customer spends in the system (W).

The theorem, stated simply as L = \(\lambda W\), applies to a wide range of queueing systems, under the assumption of steady-state conditions. In our exercise, the average arrival rate and the average number of customers are known, and thus Little's theorem can directly provide the average time a customer spends in the system. It's a powerful result that is widely used due to its general applicability and simplicity.

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Most popular questions from this chapter

Compare the \(M / G / 1\) system for first-come, first-served queue discipline with one of last-come, first-served (for instance, in which units for service are taken from the top of a stack). Would you think that the queue size, waiting time, and busyperiod distribution differ? What about their means? What if the queue discipline was always to choose at random among those waiting? Intuitively, which discipline would result in the smallest variance in the waiting time distribution?

Consider a queueing system having two servers and no queue. There are two types of customers. Type 1 customers arrive according to a Poisson process having rate \(\lambda_{1}\), and will enter the system if either server is free. The service time of a type 1 customer is exponential with rate \(\mu_{1}\). Type 2 customers arrive according to a Poisson process having rate \(\lambda_{2}\). A type 2 customer requires the simultaneous use of both servers; hence, a type 2 arrival will only enter the system if both servers are free. The time that it takes (the two servers) to serve a type 2 customer is exponential with rate \(\mu_{2}\). Once a service is completed on a customer, that customer departs the system. (a) Define states to analyze the preceding model. (b) Give the balance equations. In terms of the solution of the balance equations, find (c) the average amount of time an entering customer spends in the system; (d) the fraction of served customers that are type \(1 .\)

Customers arrive at a single-server station in accordance with a Poisson process with rate \(\lambda\). All arrivals that find the server free immediately enter service. All service times are exponentially distributed with rate \(\mu\). An arrival that finds the server busy will leave the system and roam around "in orbit" for an exponential time with rate \(\theta\) at which time it will then return. If the server is busy when an orbiting customer returns, then that customer returns to orbit for another exponential time with rate \(\theta\) before returning again. An arrival that finds the server busy and \(N\) other customers in orbit will depart and not return. That is, \(N\) is the maximum number of customers in orbit. (a) Define states. (b) Give the balance equations. In terms of the solution of the balance equations, find (c) the proportion of all customers that are eventually served; (d) the average time that a served customer spends waiting in orbit.

For the \(M / G / 1\) queue, let \(X_{n}\) denote the number in the system left behind by the nth departure. (a) If $$ X_{n+1}=\left\\{\begin{array}{ll} X_{n}-1+Y_{n}, & \text { if } X_{n} \geqslant 1 \\ Y_{n}, & \text { if } X_{n}=0 \end{array}\right. $$ what does \(Y_{n}\) represent? (b) Rewrite the preceding as $$ X_{n+1}=X_{n}-1+Y_{n}+\delta_{n} $$ where $$ \delta_{n}=\left\\{\begin{array}{ll} 1, & \text { if } X_{n}=0 \\ 0, & \text { if } X_{n} \geqslant 1 \end{array}\right. $$ Take expectations and let \(n \rightarrow \infty\) in Equation ( \(8.64\) ) to obtain $$ E\left[\delta_{\infty}\right]=1-\lambda E[S] $$ (c) Square both sides of Equation \((8.64)\), take expectations, and then let \(n \rightarrow \infty\) to obtain $$ E\left[X_{\infty}\right]=\frac{\lambda^{2} E\left[S^{2}\right]}{2(1-\lambda E[S])}+\lambda E[S] $$ (d) Argue that \(E\left[X_{\infty}\right]\), the average number as seen by a departure, is equal to \(L\).

Arrivals to a three-server system are according to a Poisson process with rate \(\lambda\). Arrivals finding server 1 free enter service with \(1 .\) Arrivals finding 1 busy but 2 free enter service with \(2 .\) Arrivals finding both 1 and 2 busy do not join the system. After completion of service at either 1 or 2 the customer will then either go to server 3 if 3 is free or depart the system if 3 is busy. After service at 3 customers depart the system. The service times at \(i\) are exponential with rate \(\mu_{i}, i=1,2,3\). (a) Define states to analyze the above system. (b) Give the balance equations. (c) In terms of the solution of the balance equations, what is the average time that an entering customer spends in the system? (d) Find the probability that a customer who arrives when the system is empty is served by server 3 .

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