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Consider a time reversible continuous-time Markov chain having infinitesimal transition rates \(q_{i j}\) and limiting probabilities \(\left\\{P_{i}\right\\} .\) Let \(A\) denote a set of states for this chain, and consider a new continuous-time Markov chain with transition rates \(q_{i j}^{*}\) given by $$ q_{i j}^{*}=\left\\{\begin{array}{ll} c q_{i j}, & \text { if } i \in A, j \notin A \\ q_{i j}, & \text { otherwise } \end{array}\right. $$ where \(c\) is an arbitrary positive number. Show that this chain remains time reversible, and find its limiting probabilities.

Short Answer

Expert verified
The new chain remains time-reversible since the detailed balance equations hold for the modified transition rates. The new limiting probabilities, P*_i, have the same functional form as the original probabilities, P_i, and are equal to them (P*_i = P_i).

Step by step solution

01

Define the new transition rates

Define Q* as the new transition rates matrix with elements q_(ij)*, given by: q_(ij)* = c * q_(ij) if i in A and j not in A q_(ij)* = q_(ij) otherwise
02

Prove time-reversibility for the new chain

For time-reversibility, we have to check if the detailed balance equations are satisfied with the new transition rates. The detailed balance equations are given by: P_i * q_(ij) = P_j * q_(ji) For states i,j such that i is in A and j is not in A, we have q_(ij)* = c * q_(ij), and q_*(ji) = q_(ji). Check the balance equations for these pairs of states: P_i * (c * q_(ij)) = P_j * q_(ji) Since the original chain was time-reversible, we know that P_i * q_(ij) = P_j * q_(ji). Therefore, the detailed balance equations also hold for the new chain with the modified transition rates for states i in A and j not in A. For all other pairs of states, q_(ij)* = q_(ij), and the detailed balance equations directly hold since they held for the original chain. Therefore, the new chain remains time-reversible.
03

Find the new limiting probabilities

To find the limiting probabilities for the new chain, we need to solve the balance equations. Define P*_i as the new limiting probabilities. The balance equations for the new chain can be written as follows: P*_i * q_(ij)* = P*_j * q_(ji)* For states i,j such that i is in A and j is not in A, we have: P*_i * (c * q_(ij)) = P*_j * q_(ji) and for all other pairs of states, we have: P*_i * q_(ij) = P*_j * q_(ji) We can see that the equations for the new limiting probabilities are essentially the same as for the original chain, with a factor of 'c' for transitions from a state in A to a state not in A. Therefore, the new limiting probabilities P*_i will have the same functional form as the original probabilities P_i, but with a normalization factor due to the modified transition rates. Let the normalization factor be k, then the new limiting probabilities can be written as: P*_i = k * P_i To find k, we need to use the condition that the probabilities must sum up to 1: sum(P*_i) = 1 Substitute P*_i, and simplify: k * sum(P_i) = 1 Since sum(P_i) = 1 for the original chain, we have k = 1. Therefore, the new limiting probabilities are equal to the original probabilities: P*_i = P_i

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Rates
In the realm of Markov chains, particularly when discussing continuous-time Markov chains, transition rates are fundamental elements that dictate the dynamics of the system. They are denoted by the symbols like \(q_{ij}\) and represent the instantaneous rate at which the process transitions from state \(i\) to state \(j\). To put it simply, the higher the transition rate \(q_{ij}\), the more frequently the system is likely to move from state \(i\) to state \(j\).

In the exercise, the concept of transition rates is expanded by introducing a new set of rates, \(q_{ij}^*\), which are modified based on whether state \(i\) is within a specified set \(A\). This modification is implemented by multiplying the original rate by a constant \(c\) when transitioning from a state in \(A\) to a state not in \(A\), and keeping it the same otherwise. It's this alteration of rates that the problem then examines, specifically regarding the time reversibility and limiting probabilities of the new chain.
Limiting Probabilities
Limiting probabilities are a cornerstone concept for understanding Markov chains. They are the probabilities to which the system settles as time progresses towards infinity. Written mathematically, if \(P_i\) is the limiting probability of state \(i\), this is the likelihood that the system is in state \(i\) after a long period. Determining limiting probabilities is a matter of solving the balance equations, ensuring that the probabilities correctly reflect the long-term behavior of the system.

In our exercise, the modification of transition rates raises the question whether these changes affect the limiting probabilities. It's somewhat intuitive to think that altering how states communicate would shift their long-term probabilities. However, the beauty of this problem lies in the demonstration that despite the changes in rates between certain states, the limiting probabilities themselves remain unaffected - as long as the process continues to satisfy the detailed balance equations.
Detailed Balance Equations
The focus on detailed balance equations is crucial when dealing with time reversibility in Markov chains. These equations ensure that for every pair of states \(i\) and \(j\), the rate of flow from \(i\) to \(j\) is exactly balanced by the rate of flow from \(j\) to \(i\), given the system's limiting probabilities. The equations are written as \(P_i q_{ij} = P_j q_{ji}\), meaning that the probability of being in state \(i\) and moving to state \(j\) equals the probability of being in state \(j\) and moving to state \(i\).

This concept is pivotal in the provided exercise, as it forms the basis for demonstrating time reversibility in the modified chain. By showing that these equalities hold even after changing the transition rates, we establish that the altered system remains in detailed balance, thus preserving the essential characteristics of a time-reversible Markov chain.
Continuous-Time Markov Chain
A continuous-time Markov chain (CTMC) is an extension of the simple Markov chain to a continuous time domain. Unlike its discrete-time counterpart where transitions occur at specific intervals, a CTMC allows for changes between states at any point in time, guided by the transition rates \(q_{ij}\). This makes CTMCs particularly useful for modeling real-world processes that don't operate on a synchronized clock.

The original exercise illustrates a time reversible CTMC, which is a specific type of CTMC having the property that the system behaves the same way forward in time as it does in reverse, given the detailed balance conditions are satisfied. This time reversibility is an insightful property that simplifies many aspects of the mathematical treatment of such chains, including the analysis of their equilibrium behavior and calculation of limiting probabilities.

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Most popular questions from this chapter

Suppose that a one-celled organism can be in one of two states-either \(A\) or \(B\). An individual in state \(A\) will change to state \(B\) at an exponential rate \(\alpha ;\) an individual in state \(B\) divides into two new individuals of type \(A\) at an exponential rate \(\beta .\) Define an appropriate continuous- time Markov chain for a population of such organisms and determine the appropriate parameters for this model.

Each time a machine is repaired it remains up for an exponentially distributed time with rate \(\lambda\). It then fails, and its failure is either of two types. If it is a type 1 failure, then the time to repair the machine is exponential with rate \(\mu_{1}\); if it is a type 2 failure, then the repair time is exponential with rate \(\mu_{2} .\) Each failure is, independently of the time it took the machine to fail, a type 1 failure with probability \(p\) and a type 2 failure with probability \(1-p\). What proportion of time is the machine down due to a type 1 failure? What proportion of time is it down due to a type 2 failure? What proportion of time is it up?

Consider a system of \(n\) components such that the working times of component \(i, i=1, \ldots, n\), are exponentially distributed with rate \(\lambda_{i} .\) When a component fails, however, the repair rate of component \(i\) depends on how many other components are down. Specifically, suppose that the instantaneous repair rate of component \(i, i=1, \ldots, n\), when there are a total of \(k\) failed components, is \(\alpha^{k} \mu_{i}\) (a) Explain how we can analyze the preceding as a continuous-time Markov chain. Define the states and give the parameters of the chain. (b) Show that, in steady state, the chain is time reversible and compute the limiting probabilities.

A single repairperson looks after both machines 1 and \(2 .\) Each time it is repaired, machine \(i\) stays up for an exponential time with rate \(\lambda_{i}, i=1,2 .\) When machine \(i\) fails, it requires an exponentially distributed amount of work with rate \(\mu_{i}\) to complete its repair. The repairperson will always service machine 1 when it is down. For instance, if machine 1 fails while 2 is being repaired, then the repairperson will immediately stop work on machine 2 and start on \(1 .\) What proportion of time is machine 2 down?

(a) Show that Approximation 1 of Section \(6.8\) is equivalent to uniformizing the continuous-time Markov chain with a value \(v\) such that \(v t=n\) and then approximating \(P_{i j}(t)\) by \(P_{i j}^{* n}\). (b) Explain why the preceding should make a good approximation. Hint: What is the standard deviation of a Poisson random variable with mean \(n\) ?

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