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The average waiting time in a doctor’s office varies. The standard deviation of waiting times in a doctor’s office is 3.4 minutes. A random sample of 30 patients in the doctor’s office has a standard deviation of waiting times of 4.1 minutes. One doctor believes the variance of waiting times is greater than originally thought.

What type of test should be used?

Short Answer

Expert verified

A test of single variance should be used.

Step by step solution

01

Given Information

The average waiting time in a doctor’s office varies. The standard deviation of waiting times in a doctor’s office is 3.4 minutes. A random sample of 30 patients in the doctor’s office has a standard deviation of waiting times of 4.1 minutes .

02

Explanation

We have to find what type of test should be used:

The average waiting time in a doctor’s office varies.

The standard deviation of waiting times in a doctor’s office is 3.4minutes.

A random sample of 30patients in the doctor’s office has a standard deviation of waiting times of 4.1minutes.

We have learned that, the chi-square examination for single variance can be used where population variance is similar to some selected values.

Therefore, a test of single variance should be applied here.

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Most popular questions from this chapter

Use a goodness-of-fit test to determine if high school principals believe that students are absent equally during the week or not.

Table 11.42contains information from a survey among 499participants classified according to their age groups. The second column shows the percentage of obese people per age class among the study participants. The last column comes from a different study at the national level that shows the corresponding percentages of obese people in the same age classes in the USA. Perform a hypothesis test at the 5% significance level to determine whether the survey participants are a representative sample of the USA obese population.

Age Class (Years) Obese Expected (percentage) Obese Observed (Frequencies)
20-30
22.4
122
31-40
18.6
104
41-50
12.8
78
51-60
10.4
64
61-70
35.8
168

Table11.42

Suppose an airline claims that its flights are consistently on time with an average delay of at most 15 minutes. It claims that the average delay is so consistent that the variance is no more than 150 minutes. Doubting the consistency part of the claim, a disgruntled traveler calculates the delays for his next 25 flights. The average delay for those 25 flights is 22 minutes with a standard deviation of 15 minutes.

How did you know to test the variance instead of the mean?

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The mean and the median of the chi-square distribution are the same if df=24.

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