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α=0.01

a. Decision: ___________________

b. Reason for the decision: ___________________

c. Conclusion (write out in a complete sentence): ___________________

Short Answer

Expert verified

The null hypothesis is rejected since the p-value is less thanα

Step by step solution

01

Given Information

Given data:

α=0.01.

02

Explanation

Decision: α=0.01, reject the null hypothesis.

Reason for the decision: Pvalue=0which is less than α=0.01

Conclusion : There is enough information to suggest that the level of smoking varies by ethnic group.

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Most popular questions from this chapter

Table 11.42contains information from a survey among 499participants classified according to their age groups. The second column shows the percentage of obese people per age class among the study participants. The last column comes from a different study at the national level that shows the corresponding percentages of obese people in the same age classes in the USA. Perform a hypothesis test at the 5% significance level to determine whether the survey participants are a representative sample of the USA obese population.

Age Class (Years) Obese Expected (percentage) Obese Observed (Frequencies)
20-30
22.4
122
31-40
18.6
104
41-50
12.8
78
51-60
10.4
64
61-70
35.8
168

Table11.42

The standard deviation of heights for students in a school is 0.81. A random sample of 50students is taken, and the standard deviation of heights of the sample is 0.96. A researcher in charge of the study believes the standard deviation of heights for the school is greater than 0.81.

To find the value ofdf.

The mean and the median of the chi-square distribution are the same if df=24.

Use a goodness-of-fit test to determine if high school principals believe that students are absent equally during the week or not.

The expected percentage of the number of pets students have in their homes is distributed (this is the given distribution for the student population of the United States) as in Table 11.12.

Number of PetsPercent0181252303184+9

A random sample of 1,000students from the Eastern United States resulted in the data in Table 11.13.

Number of PetsFrequency02101240232031404+90

At the 1% significance level, does it appear that the distribution “number of pets” of students in the Eastern United States is different from the distribution for the United States student population as a whole? What is the p-value?

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