Logout Open In App
Open In App
Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Chapter 11: Q.39 (page 657)

Is this a right-tailed, left-tailed, or two-tailed test? Explain why.

Short Answer

Expert verified

It is a right-tailed test.

Step by step solution

01

Given Information

Given data:

02

Explanation

The test of independence is always a right-tailed test, depending on how the test statistic is calculated.

We can assume that because observed values are not close together, big test statistics will result, and this test statistic will fall on the right tail of the chi-square curve, as it does in a goodness-of-fit test.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

df= ________

You want to buy a specific computer. A sales representative of the manufacturer claims that retail stores sell this computer at an average price of \(1,249 with a very narrow standard deviation of \)25. You find a website that has a price comparison for the same computer at a series of stores as follows: \(1,299;\)1,229.99;\(1,193.08;\)1,279;\(1,224.95;\)1,229.99;\(1,269.95;\)1,249. Can you argue that pricing has a larger standard deviation than claimed by the manufacturer? Use the 5% significance level. As a potential buyer, what would be the practical conclusion from your analysis?

use a solution sheet to solve the hypothesis test problem. Go to Appendix E for the chi-square solution sheet. Round expected frequency to two decimal places car manufacturers are interested in whether there is a relationship between the size of the car an individual drives and the number of people in the driver’s family (that is, whether car size and family size are independent).To test this, suppose that 800car owners were randomly surveyed with the results in Table 11.44. Conduct a test of independence.

Family SizeSub & CompactMid-sizeFull-sizeVan & Truck
1
20
35
40
35
2
20
50
70
80
3-4
20
50
100
90
5+
20
30
70
70

Table 11.44

a. Explain why a goodness-of-fit test and a test of independence are generally right-tailed tests.

b. If you did a left-tailed test, what would you be testing?

The Bureau of Labor Statistics gathers data about employment in the United States. A sample is taken to calculate the number of U.S. citizens working in one of several industry sectors over time. Table 11.17 shows the results:

Industry Sector200020102020TotalNonagriculture wage and salary13,24313,04415,01841,305Goods-producing, excluding agriculture2,4571,7711,9506,178Services-providing10,78611,27313,06835,127Agriculture, forestry, fishing, and hunting240214201655Nonagriculture self-employed and unpaid family worker9318949722,797Secondary wage and salary jobs in agriculture and private householdindustries14111136Secondary jobs as a self-employed or unpaid family worker196144152492Total27,86727,35131,37286,590

We want to know if the change in the number of jobs is independent of the change in years. State the null and alternative hypotheses and the degrees of freedom .
See all solutions

Recommended explanations on Math Textbooks

Geometry

Read Explanation

Probability and Statistics

Read Explanation

Pure Maths

Read Explanation

Calculus

Read Explanation

Mechanics Maths

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free