Question

What can you conclude at the $5\%$ level of significance?

Short answer

Take decision that "reject the null hypothesis $H_0$"because $p-$value $<\alpha$so the given $p-$value is $0$ so the "null hypothesis" was rejected, but the alternate hypothesis was approved, therefore there will be enough evidence to show that a passenger's ticket class selection is based on the distance they must go.

Step-by-step solution

Given Information

Given data:

$\begin{array}{|llllll|}\hline & \text{A}& \text{B}& \text{C}& \text{D}& \text{E}\\ 1& \text{Given Table (Observed Frequency)}& & & & \\ 2& \text{Traveling Distance}& \text{Third Class}& \text{Second Class}& \text{First Class}& \text{Total}\\ 3& 1-100\text{miles}& 21& 14& 6& 41\\ 4& 101-200\text{miles}& 18& 16& 8& 42\\ 5& 201-300\text{miles}& 16& 17& 15& 48\\ 6& 301-400\text{miles}& 12& 14& 21& 47\\ 7& 401-500\text{miles}& 6& 6& 10& 22\\ 8& \text{Total}& 73& 67& 60& 200\\ \hline\end{array}$

Explanation

Take decision that "reject the null hypothesis $H_0$"because $p-$value $<\alpha$so the given p-value is $0$ so the "null hypothesis" was rejected, but the alternate hypothesis was approved, therefore there will be enough evidence to show that a passenger's ticket class selection is based on the distance they must go.