Chapter 11: Q.114 (page 668)
chi-square test statistic = ________
Short Answer
chi-square test statistic =
Chapter 11: Q.114 (page 668)
chi-square test statistic = ________
chi-square test statistic =
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Get started for freeTeachers want to know which night each week their students are doing most of their homework. Most teachers think that students do homework equally throughout the week. Suppose a random sample of 56 students were asked on which night of the week they did the most homework. The results were distributed as in Table 11.8.
From the population of students, do the nights for the highest number of students doing the majority of their homework occur with equal frequencies during a week? What type of hypothesis test should you use?
Use the following information to answer the next nine exercise: The following data are real. the cumulative number of AIDS cases reported for Santa Clary Country is broken down by ethnicity as in table 11.29
The percentage of each ethnic group in Santa Clary Country is as in Table shown below
If the ethnicities of AIDS victims followed the ethnicities of the total country population, fill in the expected number of cases per ethnic group.
Perform a goodness-of-fit test to determine whether the occurance of AIDS cases follows the ethnicities of the general population of Santa Clary Country
Conduct a goodness-of-fit test to determine if the actual college majors of graduating females fit the distribution of their expected majors.
Major | Women -Expected Major | Wome -Actual Major |
Arts & Humaities | 14.0% | 670 |
Biological Sciences | 8.4% | 410 |
Business | 13.1% | 685 |
Education | 13.0% | 650 |
Engineering | 2.6% | 145 |
Physical Sciences | 2.6% | 125 |
Professional | 18.9% | 975 |
Social Sciences | 13.0% | 605 |
Technical | 0.4% | 15 |
Other | 5.8% | 300 |
Undecided | 8.0% | 420 |
The manager of "Frenchies" is concerned that patrons are not consistently receiving the same amount of French fries with each order. The chef claims that the standard deviation for a ten-ounce order of fries is at most oz., but the manager thinks that it may be higher. He randomly weighs orders of fries, which yields a mean of oz. and a standard deviation of two oz.
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