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Graph the situation. Label and scale the horizontal axis. Mark the mean and test statistic. Shade in the region corresponding to the p-value.

Short Answer

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The graph:

Step by step solution

01

Given Information

Given data:

02

Explanation

α=0.05So take a decision "reject the null hypothesis H0"because p-value<αso p--value is 0.

As a result of "rejecting the null hypothesis," the alternative hypothesis was accepted, and there is sufficient data to suggest that self-reported ethnicity is influenced by daily smoking levels.

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Most popular questions from this chapter

A teacher predict that the distribution of grades on the final exam will be and they are recorded in table 11.27

The actual distribution for a class of 20 is in table 11.28

State the null and alternative hypothesis

Read the statement and decide whether it is true or false.

The test to use to determine if a six-sided die is fair is a goodness-of-fit test.

Use a solution sheet to solve the hypothesis test problem. Go to Appendix E for the chi-square solution sheet. Round expected frequency to two decimal places College students may be interested in whether or not their majors have any effect on starting-salaries after graduation. Suppose that 300recent graduates were surveyed as to their majors in college and their starting salaries after graduation. Table 11.45shows the data. Conduct a test of independence.

Major<\(50,000
\)50,000-\(68,999\)69,000+
English5
205
Engineering10
3060
Nursing10
1515
Business10
20
30
Psychology20
3020

Table11.45

Determine the appropriate test to be used in the next three exercises.

A personal trainer is putting together a weight-lifting program for her clients. For a 90-day program, she expects each client to lift a specific maximum weight each week. As she goes along, she records the actual maximum weights her clients lifted. She wants to know how well her expectations met with what was observed.

The manager of "Frenchies" is concerned that patrons are not consistently receiving the same amount of French fries with each order. The chef claims that the standard deviation for a ten-ounce order of fries is at most 1.5oz., but the manager thinks that it may be higher. He randomly weighs49 orders of fries, which yields a mean of 11 oz. and a standard deviation of two oz.

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