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A typical adult has an average IQ score of 105with a standard deviation of 20. If 20randomly selected adults are given an IQ test, what are the probability that the sample mean scores will be between 85 and 125 points?

Short Answer

Expert verified

The probability that the sample mean scores will be between 85 and 125points is1.

Step by step solution

01

Given Information

what is the probability that the sample mean scores will be between 85and125 points?

02

Explanation

LetvariableXrepresentIQscore of a person. The distribution ofX:

X~N(105,20)

The distribution of the average score of 20 people

X¯~N(105,2020)~N(20,20)

Finding the wanted probability:

localid="1650524594045" P(85<X<125)=P(8510520<X¯10520<12510520)

=ϕ(12510520)ϕ(8510520)

=ϕ(4.47)ϕ(4.47)

=2ϕ(4.47)1

=2-1

=1

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Most popular questions from this chapter

M&M candies large candy bags have a claimed net weight of 396.9g. The standard deviation for the weight of the

individual candies is 0.017g. The following table is from a stats experiment conducted by a statistics class.

RedOrangeYellowBrownBlueGreen
0.751
0.735
0.883
0.696
0.881
0.925
0.841
0.895
0.769
0.876
0.863
0.914
0.856
0.865
0.859
0.855
0.775
0.881
0.799
0.864
0.784
0.8060.854
0.865
0.966
0.852
0.824
0.840
0.810
0.865
0.859
0.866
0.858
0.868
0.858
1.015
0.857
0.859
0.848
0.859
0.818
0.876
0.942
0.838
0.851
0.982
0.868
0.809
0.873
0.863


0.803
0.865
0.809
0.888


0.932
0.848
0.890
0.925


0.842
0.940
0.878
0.793


0.832
0.833
0.905
0.977


0.807
0.845

0.850


0.841
0.852

0.830


0.932
0.778

0.856


0.833
0.814

0.842


0.881
0.791

0.778


0.818
0.810

0.786


0.864
0.881

0.853


0.825


0.864


0.855


0.873


0.942


0.880


0.825


0.882


0.869


0.931


0.912





0.887

The bag contained 465candies and the listed weights in the table came from randomly selected candies. Count the weights.

a. Find the mean sample weight and the standard deviation of the sample weights of candies in the table.

b. Find the sum of the sample weights in the table and the standard deviation of the sum of the weights.

c. If 465M&Ms are randomly selected, find the probability that their weights sum to at least 396.9.

d. Is the Mars Company’s M&M labeling accurate?

Find the probability that the sample mean is between seven and 11

A manufacturer produces 25-pound lifting weights. The lowest actual weight is 24pounds, and the highest is 26pounds. Each weight is equally likely so the distribution of weights is uniform. A sample of 100weights is taken.

a. What is the distribution for the weights of one 25-pound lifting weight? What is the mean and standard deviation?

b. What is the distribution for the mean weight of 100,25-pound lifting weights?

c. Find the probability that the mean actual weight for the 100 weights is less than 24.9.

Determine which of the following are true and which are false. Then, in complete sentences, justify your answers.

a. When the sample size is large, the mean of X¯is approximately equal to the mean of X.

b. When the sample size is large, X¯is approximately normally distributed.

c. When the sample size is large, the standard deviation of X¯is approximately the same as the standard deviation of X.

Use the following information to answer the next six exercises: Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2hours. Let Xbe the random variable representing the time it takes her to complete one review. Assume Xis normally distributed. Let Xbe the random variable representing the mean time to complete the 16 reviews. Assume that the 16 reviews represent a random set of reviews.

1. What is the mean, standard deviation, and sample size?

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