Question

An unknown distribution has a mean of $80$and a standard deviation of $12$. A sample size of $95$is drawn randomly from the population.

Find the probability that the sum of the $95$values is greater than $7650$.

Short answer

The value probability that the sum of $95$values is greater than $7650$is =$0.3345$

Step-by-step solution

Given Information

Given in the question that, mean =$80$

standard deviation is$12$

Find the probability that the sum of the 95 values is greater than 7,650.

Explanation

From the information given in the question, the sample size of $95$is randomly drowned from the population with a mean of $80$and the standard deviation is $12$.

We have to use Ti-83 calculator to find the probability that the totality of $95$values is greater than $7650$.

For this, click on $2$^as , then DISTR, and then scroll down to the normal CDF option and enter the supplied details. After this, click on ENTER button on the calculator to have the preferred result.

Explanation

The screenshot is given below:

Therefore, the value probability that the sum of $95$values is greater than $7650$is:

$=1-0.66548$

$=0.3345$