Question

Find the probability that the sum of the $100$ values falls between the numbers you found in and.

Short answer

The probability that the sum of the $100$ values falls between$P(3900<\Sigma X<3910)=0.5433$.

Step-by-step solution

Given Information

The researcher randomly selects a sample$\left(n\right)$ is $100$.

Explanation

To find the probability that the sum of the $100$values falls between$\mathrm{P}(3900<\Sigma X<3910)$:$=\mathrm{P}\left(\frac{3900-3901}{5}<Z<\frac{3910-3901}{5}\right)$

$=\mathrm{P}(-0.2<Z<1.8)$

$=\mathrm{P}(Z<1.8)-Pr(Z<-0.2)$

$=0.9641-0.4208$

$=0.5433$