Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Based on data from the National Health Survey, women between the ages of 18and 24have an average systolic blood pressures (in mm Hg) of 114.8with a standard deviation of 13.1. Systolic blood pressure for women between the ages of 18 to 24follow a normal distribution.
a. If one woman from this population is randomly selected, find the probability that her systolic blood pressure is greater than120 .
b. If 40 women from this population are randomly selected, find the probability that their mean systolic blood pressure is greater than 120 .
c. If the sample were four women between the ages of 18to 24 and we did not know the original distribution, could the central limit theorem be used?

Short Answer

Expert verified

(a) The probability that the systolic blood pressure is greater than120is0.3516
(b) The probability that the mean systolic blood pressure is greater than 120isPr(X¯120)=0.475
(c) Can not use the central limit theorem.

Step by step solution

01

Given information Part (a)

Women between the ages of18and24have an average systolic blood pressures of114.8with a standard deviation of13.1.

02

Explanation Part (a)

According to the information, we observed thatμ=114.8and σ=13.1
Let's consider:Pr(X120).
Now, apply exponential distribution for an individual:

X~Exp(1114.8)

P(x>120)=e1114.8(120)

=e1.0453=0.3516

03

Given information Part (b)

The probability that their mean systolic blood pressure is greater than 120. To compute the probability by usingPr(X¯120).

04

Explanation Part (b)

From the given information, we observed thatX¯~N(114.8,13.1×40)where n=40
We have to find the probability for 40 women, that their mean systolic blood pressure is greater than 120

So, let's computePr(X¯120)
Pr(X¯120)=PrZ120114.882.85=Pr(Z0.0628)

Pr(X¯120)=0.475

05

Given information Part (c)

Women between the ages of 18and 24have an average systolic blood pressures of 114.8with a standard deviation of13.1

06

Explanation Part (c)

If the sample were four women between the ages of 18 to 24, did not understand the original distribution and could not utilize the central limit theorem because the sample size was too short and did not notice the distribution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of \(4.59and a standard deviation of \)0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16gas stations. The distribution to use for the average cost of gasoline for the 16gas stations is:

a.X¯~N(4.59,0.10)

b.X¯~N4.59,0.1016

c.X¯~N4.59,160.10

d.X¯~N4.59,160.10

Find the sum that is 1.5 standard deviations below the mean of the sums.

The length of time a particular smartphone's battery lasts follows an exponential distribution with a mean of ten months. A sample of 64 of these smartphones is taken.

Find the IQR for the mean amount of time 64 batteries last.

Find the probability that the sums will fall between the z-scores 2 and 1.

Previously, De Anza statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of \(0.88. Suppose that we randomly pick 25daytime statistics students.

a. In words,Χ=____________

b.Χ~_____(_____,_____)

c.role="math" localid="1651578876947" Inwords,X=____________

d. X~______(______,______)

e. Find the probability that an individual had between \)0.80and\(1.00. Graph the situation, and shade in the area to be determined.

f. Find the probability that the average of the 25 students was between \)0.80and$1.00. Graph the situation, and shade in the area to be determined.

g. Explain why there is a difference in part e and part f.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free