Question

A manufacturer produces $25$-pound lifting weights. The lowest actual weight is $24$pounds, and the highest is $26$pounds. Each weight is equally likely so the distribution of weights is uniform. A sample of $100$weights is taken.

Draw the graph from Exercise$7.41$

Short answer

The graph is

Step-by-step solution

Given Information

We have $25$-pound lifting weights. The lowest actual weight is $24$ pounds, and the highest is $26$ pounds. The distribution of weights is uniform.

Explanation

From Example, $7.41$we know:

The mean of the uniform distribution is

${\mu }_X=\frac{a+b}{2}$

$=\frac{24+26}{2}$

$=25$

The standard deviation is

${\sigma }_x=\sqrt{\frac{(b-a{)}^2}{12}}$

$=\sqrt{\frac{(26-24{)}^2}{12}}$

$=\sqrt{\frac{4}{12}}$

$=0.5774$

The distribution of the mean weight of $100,25$-pounds is

$\overline{X}~N\left({\mu }_X,{\sigma }_X/\sqrt{n}\right)$

$\overline{X}~N(25,0.0577)$

Also, in Example $7.41$we calculate ${90}^{\text{th}}$ percentile for the mean weight for $100$ weights is$25.07$

Final Answer

The graph for our Example is