Question

Find the percentage of sums between 1.5 standard deviations below the mean and one standard deviation above the mean.

Short answer

MEAN is used to calculate the entire data in statistical terms.

Step-by-step solution

Given information

Explanation:

The sample size of forty is randomly drowned from cholesterol with mean$180$and standard deviation$20$. The mean of sums is given as:

$\sum X=\left(n\right)\left({\mu }_X\right)-\left(z\right)\left(\sqrt{n}\right)\left({\sigma }_X\right)$

$7326.49$

The sum that is$1.5$the standard deviation below the mean of the $7010.26$sum is given as;

$\mathrm{\Sigma }X=\left(n\right)\left({\mu }_X\right)-\left(z\right)\left(\sqrt{n}\right)\left({\sigma }_X\right)$

$7010.26$

The percentage for the sums between the standard deviation below the mean of sums and the standard deviation above the mean of the sum is 77.45%.

Final answer

The percentage for the given standard deviation is 77.45%.