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Use the following information to answer the next six exercises. A jar of 150jelly beans contains 22red jelly beans, 38

yellow, 20green, 28purple, 26blue, and the rest are orange.

Let B = the event of getting a blue jelly bean

Let G = the event of getting a green jelly bean.

Let O = the event of getting an orange jelly bean.

Let P = the event of getting a purple jelly bean.

Let R = the event of getting a red jelly bean.

Let Y = the event of getting a yellow jelly bean.

Find P(Y).

Short Answer

Expert verified

The solution is

P(Y)=38150=1975=0.25

Step by step solution

01

Given information

Weareprovidedthefollowinginformationinthegivenquestion:
22red jelly beans,38yellow jelly beans, 20green jelly beans, 28purple jelly beans, 26blue jelly beans, and the rest are orange jelly beans make up a jar of 150jelly beans.
02

Concept used

Probabilityisametricfordetermininghowcertainweareoftheresultsofacertainexperiment.
Theprobabilityiscalculatedusingthefollowingformula:
Probability

=Farorable number of casesTotal number of cases

If we flip a coin twice, the sample space associated with this random experiment is H, H T, T H, T T, where T= tails and H= heads.
Let's say A= only has one tail.
Because localid="1648041984677" P(A)=24=0.5, there are two outcomes that favor the event A H T, T H.
03

Calculation

Number of orange jelly beans

localid="1651638322634" =150-(22+38+20+28+26)=150-134=16

Let B= the event of getting a blue jelly bean

Let G=the event of getting a green jelly bean.

Let O= the event of getting an orange jelly bean.

Let P= the event of getting a purple jelly bean.

Let R= the event of getting a red jelly bean.

Let Y= the event of getting a yellow jelly bean.

Now to find the probability of getting a yellow jelly bean, the favorable number of cases is 38and total cases are 150 . Therefore, the probability of getting a yellow jelly bean is:

localid="1648042037831" P(Y)=38150=1975=0.25

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